Let's say x is the amount of money Kelly saves. We do not know how many weeks she is saving. If she was saving for 2, then the equation would be x=5(2). However, she is saving by w weeks, so the equation is x=5w.
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
My answer:
Scale Drawing Lengths: . . / .
Actual Court Lengths . . .
Scale Factor: inch corresponds to ( ∙ ) inches, or inches, so the scale factor is .
Let = , represent the scale drawing lengths in inches, and represent the actual court lengths in inches. The -values must be converted from feet to inches.
To find actual length:
= =
() = inches, or feet
To find actual width:
= = ( )
= / ∙ /
= inches, or feet
The actual court measures feet by feet. Yes, the lot is big enough for the court Vincent planned. The court will take up the entire width of the lot.
1.5= 1 lap+ 0.5 lap = [2(85)+pi*(d)] + [85+pi*d/2]= 3[(85)+pi*d(1/2)]
just substitute d=74
The answer is (-7.5, -7.5)
Answer:

Step-by-step explanation:
We have the product,
.
It is known that,
'When we multiply a scalar with a matrix, the scalar is multiplied by each element of the matrix'.
So, we get,
.
⇒ 
⇒ 
So, the resulting product is
.