Question

The sum of three consecutive multiples of 4 is 444. Find these multiples.

Answer 1

First multiple of 4 is x = 144

Second multiple of 4 is x + 4 = 144 + 4 = 148

Third multiple of 4 is x + 8 = 144 + 8 = 152

Answer 2

Step-by-step explanation:

Let the first multiple of 4 be x and second multiple be (x + 4) and third multiple be (x + 8) ...[Since, the number are consecutive multiple of 4]

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies \sf x \: + \: x \: + \: 4 \: + \: x \: + \: 8 \: = \: 444$

$:\implies \sf 3x \: + \: 12 \: = \: 444$

$:\implies \sf 3x \: = \: 444 \: - \: 12$

$:\implies \sf 3x \: = \: 432$

$:\implies \sf x \: = \: \dfrac{432}{3}$

$:\implies\underline{ \boxed{\sf x \: = \: 144}}$

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Therefore,

$\bullet\:\:\textsf{First multiple of 4 = x = \textbf{144}}$

$\bullet\:\:\textsf{Second multiple of 4 = x + 4 = 144 + 4 = \textbf{148}}$

$\bullet\:\:\textsf{Third multiple of 4 = x + 8 = 144 + 8 = \textbf{152}}$