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3 years ago

Which equation is written in slope-intercept form?

Mathematics

1 answer:

zhuklara [117]3 years ago

3 0

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y = mx + b

m - slope

b - y-intercept

We have

A. y = 3x - 2 - it's the slope-intercept form

B. x = 1/2y + 8 NOT

C. 2x + 5y = 12 NOT - it's the standard form

D. 3y = 8x - 5 NOT

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Percentage of words starting with T

Mkey [24]

Do what the hint says lol

4 0

2 years ago

Which is a better price: 5 for $1.00, 4 for $0.85, 2 for $0.25, or 6 for $1.10?

Angelina_Jolie [31]

Answer:

2 for $0.25

Step-by-step explanation:

1.10/ 6= .20 (rounding)

1.00/ 5= .20

0.85/ 4= .21

0.25/ 2= .13 (rounding)

4 0

4 years ago

What is AE ? Enter your answer in the box. units Two segments A D and B C intersect at point E to form two triangles A B E and D

spin [16.1K]

Answer:

The length of AE is 20 units.

Step-by-step explanation:

Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.

we have to find the length of AE

AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD

In ΔABE and ΔDCE

∠EAB=∠EDC (∵Alternate angles)

∠EBA=∠ECD (∵Alternate angles)

By AA similarity, ΔABE ≈ ΔDCE

therefore, $\frac{AE}{ED}=\frac{AB}{CD}$

⇒ $\frac{2x+10}{x+3}=\frac{10}{4}$

⇒ $8x+40=10x+30$

⇒ $x=5$

Hence, AE=2x+10=2(5)+10=20 units

The length of AE is 20 units.

5 0

4 years ago

AB and DE are chords that intersect at point F inside circle C as shown. If the measure of arc EA= 50 degrees and the measure of

defon

Answer:

Part 1) $m\angle AFE=55^o$

Part 2) $m\angle EFB=125^o$

Step-by-step explanation:

Part 1) what is the measure of angle AFE

we know that

The measure of the interior angle is the semisum of the arches that comprise it and its opposite.

Note: In this problem the correct measure of arc EA is 40 degrees (see the picture)

$m\angle AFE=\frac{1}{2}(arc\ EA+arc\ DB)$

substitute the given values

$m\angle AFE=\frac{1}{2}(40^o+70^o)=55^o$

Part 2) what is the measure of angle EFB?

we know that

$m\angle AFE+m\angle EFB=180^o$ ---> by supplementary angles (form a linear pair)

substitute the given value

$55^o+m\angle EFB=180^o$

$m\angle EFB=180^o-55^o=125^o$

8 0

4 years ago

Help please with math

yuradex [85]

Here you go, sometimes, quizlet is there with just the right info. Ur welcome.

5 0

4 years ago