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Anit [1.1K]
3 years ago
12

Brenda has two pieces of string, one 28 feet long and the other 42 feet long. For an art project, she wants to cut them up to pr

oduce many pieces of string that are all of the same length, with no string left over. What is the greatest length, in feet, that she can make them?
Mathematics
1 answer:
NeTakaya3 years ago
3 0

Answer:

7 feet

Step-by-step explanation:

Length of one piece of string = 28 feet.

Length of the second string = 42 feet.

Since the number of required pieces was not given but many are required, the greatest length can be determined by;

If the maximum length is 7 feet, then:

the number of pieces from 28 feet long string = \frac{28}{7}

                                                      = 4

Also,

the number of pieces from the 42 feet lone string = \frac{42}{7}

                                                    = 6

Total number of 7 feet strings that she can make = 4 + 6

                                                    = 10

Since many pieces are required, the greatest length she can make is 7 feet. If she increase the length to 14 feet, the number of pieces would be 5 which limit the required number.

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For a trip, one high school rented and filled 5 vans and 6 buses with 187 students. Another high school instead fit its 176 stud
serious [3.7K]

Answer:

A bus can carry 22 students and a van can carry 11 students.

Step-by-step explanation:

Let the number of students bus can carry be 'b'.

Let the number of students van can carry be 'v'.

Given:

One High school:

Number of bus = 6

Number of vans = 5

Number of students = 187

So we can say that;

Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.

framing in equation form we get;

6b+5v=187  ⇒ Equation 1

Also Given:

One High school:

Number of bus = 7

Number of vans = 2

Number of students = 176

So we can say that;

Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.

framing in equation form we get;

7b+2v=176  ⇒ Equation 2

Now multiplying equation 2 by 5  we get;

5(7b+2v)=5\times176

35b+10v=880 ⇒ Equation 3

Now multiplying Equation 1 by 2 we get;

2(6b+5v)=187\times2

12b+10v=374  ⇒ Equation 4

Subtracting equation 4 from equation 3 we get;

35b+10v-(12b+10v)=880-374\\\\35b+10v-12b-10v= 506\\\\23b =506\\\\b =\frac{506}{23} =22\ students

Substituting value of b in equation 2 we get;

7b+2v =176\\\\7\times 22+2v =176\\\\154+2v=176\\\\2v=176-154\\\\2v =22\\\\v =\frac{22}{2}=11\ students

Hence A bus can carry 22 students and a van can carry 11 students.

6 0
3 years ago
6x²+11x-2 help me fast​
Mekhanik [1.2K]

Answer:

(6x-1)(x+2)

Step-by-step explanation:

6x^2 = (6x  (x

(6x -1)(x+2)

6x * x = 6x^2

6x * 2 = 12x - 1x = 11x

-1*2 = -2

6x^2 + 11x - 2

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The pencil is 19.05 centimeters.
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2 years ago
Which expression is not equivalent to the other three A) -9- 7 + 16n
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Answer:

-16(1-n)

Step-by-step explanation:

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