3 years ago

Select the indicated real nth root(s) of a. n=3, a = 64

Mathematics

1 answer:

arsen [322]3 years ago

5 0

9514 1404 393

Answer:

Step-by-step explanation:

∛64 = ∛(4³) = 4

_____

The real root when the root index is odd will have the same sign as the value whose root it is. 64 is positive, so the real cube root will be positive.

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The following is a student’s work when solving for y. There is a mistake in the work. What is the mistake? What is the correct a

laila [671]

Answer:

Part 1

The mistake is Step 2: P + 2·x = 2·y

Part 2

The correct answer is

Step 2 correction: P - 2·x = 2·y

(P - 2·x)/2 = y

Step-by-step explanation:

Part 1

The student's steps are;

Step 1; P = 2·x + 2·y

Step 2: P + 2·x = 2·y

Step 3: P + 2·x/2 = y

The mistake in the work is in Step 2

The mistake is moving 2·x to the left hand side of the equation by adding 2·x to <em>P </em>to get; P + 2·x = 2·y

Part 2

To correct method to move 2·x to the left hand side of the equation, leaving only 2·y on the right hand side is to subtract 2·x from both sides of the equation as follows;

Step 2 correction: P - 2·x = 2·x + 2·y - 2·x = 2·x - 2·x + 2·y = 2·y

∴ P - 2·x = 2·y

(P - 2·x)/2 = y

y = (P - 2·x)/2

7 0

3 years ago

Please help me fast <br> hope its easy for ya

Ksju [112]

I think it’s the last one

8 0

3 years ago

Read 2 more answers