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3 years ago

13

Select the indicated real nth root(s) of a. n=3, a = 64

1 answer:

arsen [322]3 years ago

5 0

9514 1404 393

Answer:

4

Step-by-step explanation:

∛64 = ∛(4³) = 4

_____

The real root when the root index is odd will have the same sign as the value whose root it is. 64 is positive, so the real cube root will be positive.

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Evaluate the expression when a= 4, b= - 2, and c= 7 - -> 5a - 9 (b - c)

ollegr [7]

Answer:

$65$

Step-by-step explanation:

Given the following question:

$5a-9(b-c)$
a = 4
b = 2
c = 7

In order to find the answer, we need to substitute the variables with the numbers given, and then solve using PEMDAS.

$5\times4-9\times(2-7)$
$2-7=-5$
$5\times4-9\times-5$
$5\times4=20$
$20-9\times-5$
$9\times-5=-45$
$20--45$
$20+45=65$
$=65$

Hope this helps.

8 0

2 years ago

Domain and range and function or not<br><br>

aksik [14]

Answer:

Domain: -2,0,1,3,4

Range: 2,3

Yes its a function

Step-by-step explanation:

4 0

3 years ago

algol [13]

I can answer this for u

8 0

3 years ago

Read 2 more answers

Show how to use substitution or elimination to solve the following system of equations. Write the solution as an ordered pair.

max2010maxim [7]

Answer:

(4, 6)

Step-by-step explanation:

<u>Substitution</u>

Using the second equation, we can substitute for y in the first equation.

4x -(2x-2) = 10

2x +2 = 10 . . . . simplify

x +1 = 5 . . . . . . .divide by 2

x = 4 . . . . . . . . . subtract 1

y = 2(4) -2) = 6 . . . . substitute for x in the equation for y

The solution is (x, y) = (4, 6).

__

<u>Elimination</u>

Often, we like to start with both equations in standard form when we solve by elimination. That is nice, but not completely necessary.

We can eliminate the y-variable by simply adding the two given equations.

(4x -y) +(y) = (10) +(2x -2)

4x = 8 + 2x . . . . . collect terms. The y-variable has been eliminated.

2x = 8 . . . . . . . . . subtract 2x

x = 4 . . . . . . . . . . divide by 2

Y can be found using the second equation.

(x, y) = (4, 6)

__

We could have eliminated the x-variable by multiplying the second equation by 2, then adding the two equations.

(4x -y) +2(y) = (10) +2(2x -2)

y = 6 . . . . . . . . . subtract 4x from both sides. The x-variable has been eliminated.

Now, x can be found using either equation.

6 = 2x -2 . . . substitute for y in the second equation

3 = x - 1 . . . divide by 2

x = 4 . . . . . add 1

(x, y) = (4, 6)

3 0

3 years ago

Simplify quantity 10 x squared minus 32 end quantity over 4 quantity 5 x squared minus 32 end quantity over 2, quantity 5 x squa

irina1246 [14]

Answer:

Option B.

Step-by-step explanation:

The given expression is

$\dfrac{10x^2-32}{4}$

We need to find the simplified form of given expression.

Taking out GCF from the numerator.

$\dfrac{2(5x^2-16)}{4}$

Cancel out common factors.

$\dfrac{5x^2-16}{2}$

The expression $\dfrac{5x^2-16}{2}$ is the simplified form of given expression.

Therefore, the correct option is B.

8 0

3 years ago