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zlopas [31]
3 years ago
13

Select the indicated real nth root(s) of a. n=3, a = 64

Mathematics
1 answer:
arsen [322]3 years ago
5 0

9514 1404 393

Answer:

  4

Step-by-step explanation:

∛64 = ∛(4³) = 4

_____

The real root when the root index is odd will have the same sign as the value whose root it is. 64 is positive, so the real cube root will be positive.

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Please help me answer this show work plz
AleksAgata [21]
14 x 2000
Basic multiplication fact:
14  x   2=28
Total number of zeros=3
So, 14 x 2000=28,000
6 0
3 years ago
Read 2 more answers
The school that Trevon goes to selling tickets to the annual dance competition. On the first day of tickets sales the school sol
KiRa [710]

Answer:

  both kinds of tickets are $5 each

Step-by-step explanation:

Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:

  12s + 5c = 85 . . . . . revenue from the first day of sales

  6s + 9c = 75 . . . . . . revenue from the second day of sales

Double the second equation and subtract the first to eliminate the s variable.

  2(6s +9c) -(12s +5c) = 2(75) -(85)

  13c = 65 . . . . . simplify

  65/13 = c = 5 . . . . . divide by the coefficient of c

Substitute this value into either equation. Let's use the second one.

  6s + 9·5 = 75

  6s = 30 . . . . . . . subtract 45

  30/6 = s = 5 . . . divide by the coefficient of s

The price of a senior ticket is $5; the price of a child ticket is $5.

5 0
3 years ago
What is the inverse of f(x)=2^x
GuDViN [60]

Answer:

<h2>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h2>

Step-by-step explanation:

f(x)=2^x

y =  {2}^{x}

x =  {2}^{y}

{2}^{y}  = x

ln( {2}^{y} )=ln(x)

yln(2)=ln(x)

<h3>\frac{yln(2)}{ln(2)}  =  \frac{ln(x)}{ln(2)}</h3><h3>y =  \frac{ln(x)}{ln(2)}</h3><h3>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h3><h3>Hope it is helpful...</h3>
3 0
3 years ago
I need help with this please....Thanks
IrinaK [193]

Answer:

The total cost of redecoration is £66, that is less than £75. Tenant can decorate the room for the budget set.

Step-by-step explanation:

Lets start calculating the areas of shorter and longer walls.

The area of shorter wall is

2.65m*2.98m=7.897m^2.

The area of longer wall is

3.94m*2,65m=10.441m^2.

Together the area of one long and one short wall is

7.897m^2+10.441m^2=18.338m^2.

The area to be painted ( one short and one long wall) is 18.338m^2 that is less than 30m^2, and hence only one tin of paint is needed (costs £16).

If there is assumed that the sheets of wallpaper must be whole from floor to ceiling, the calculations are following.

We get from one roll

10m/2.65m=3.77 sheets; we can use only 3 of them

The width of the walls is 3,94m+2,98m=6,92m,

and division gives 6.92m/0.52m=13,3... .

Hence it requires 14 sheets, that is 5 rolls of wallpaper.

Wallpaper costs 5*£10=£50 and altogether it is needed £50+£16=£66 to redecorate the room.

7 0
3 years ago
If g(x)= x^2-2x-6 and h(x)= 2x^2-5x+2 find (h-g) (-2)
Natalka [10]

Answer:

<h2>(h - g)( - 2) = 18</h2>

Step-by-step explanation:

g(x) = x² - 2x - 6

h(x) = 2x² - 5x + 2

To find (h-g) (-2) we must first find h - g(x)

To find h - g(x) subtract g(x) from h(x)

We have

<h3>(h - g)(x) =  {2x}^{2}  - 5x + 2 - ( {x}^{2}  - 2x - 6)  \\  =  {2x}^{2}  - 5x + 2 -  {x}^{2}  + 2x + 6 \\  =  {2x}^{2}  -  {x}^{2}  - 5x + 2x + 2 + 6</h3><h3>(h - g)(x) =  {x}^{2}  - 3x + 8</h3>

To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2

That's

<h3>(h - g)( - 2) =  ({ - 2})^{2}  - 3( - 2) + 8 \\  = 4 + 6 + 8 \\  = 10 + 8</h3>

We have the final answer as

<h3>(h - g)( - 2) = 18</h3>

Hope this helps you

7 0
3 years ago
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