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xxTIMURxx [149]
3 years ago
9

The following is a student’s work when solving for y. There is a mistake in the work. What is the mistake? What is the correct a

nswer? Explain. Step 1: P=2x+2y Step 2: P+2x=2y Step 3: P+2x2=y
Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

Part 1

The mistake is Step 2: P + 2·x = 2·y

Part 2

The correct answer is

Step 2 correction: P - 2·x = 2·y

(P - 2·x)/2 = y

Step-by-step explanation:

Part 1

The student's steps are;

Step 1; P = 2·x + 2·y

Step 2: P + 2·x = 2·y

Step 3: P + 2·x/2 = y

The mistake in the work is in Step 2

The mistake is moving 2·x to the left hand side of the equation by adding 2·x to <em>P </em>to get; P + 2·x = 2·y

Part 2

To correct method to move 2·x to the left hand side of the equation, leaving only 2·y on the right hand side is to subtract 2·x from both sides of the equation as follows;

Step 2 correction: P - 2·x = 2·x + 2·y - 2·x = 2·x - 2·x + 2·y = 2·y

∴ P - 2·x = 2·y

(P - 2·x)/2 = y

y = (P - 2·x)/2

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n200080 [17]

Answer:

c

Step-by-step explanation:

start before a and count until you get to B

5 0
3 years ago
Please check my answers. Thanks
vaieri [72.5K]

1) should be second option

CD→

2) None of these

5 0
3 years ago
Please explain every step
pogonyaev
<h3>Answer:</h3>

761680

<h3>Explanation:</h3>

\sf \boxed{\sum _{n=1}^{44}\:60\left(1.2\right)^{n-2}}

<u>Identify the following's</u>:

First Term [a]  =  60(1.2)ⁿ⁻² = 60(1.2)¹⁻² = 50

Common ratio [r]  =  1.2

Total Terms [n] =  44

===========================

\sf Geometric \ Sum \ of  \ Terms = \dfrac{a(r^n - 1)}{r-1}

===========================

Solving Steps:

<em />\rightarrow \sf \dfrac{a(r^n - 1)}{r-1}<em />

<em />

<em />\rightarrow \sf \dfrac{50(1.2^{44} - 1)}{1.2-1}<em />

<em />

<em />\rightarrow \sf 761679.5808<em />

<em />

\rightarrow \sf 761680 \ \ \  (rounded \ to \ nearest \ integer)

8 0
2 years ago
Which equation describes a line that passes through (-6, 8) and is parallel to the line described by y = 2x − 4?
AleksandrR [38]

Answer:

hey, there!

Step-by-step explanation:

The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4

The equation for point (-6,8) is,

(y-8)= m1(x+6)...........(i)

and given equation is y = 2x-4............(ii)

Now, from equation (ii).

slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.

Now, For perpendicular,

m1×m2= -1

m1×2= -1

Therefore, m1 = -1/2.

Putting, the value of m1 in equation (i).

(y-8) = -1/2×(x+6)

2(y-8)= -1(x+6)

2y - 16 = -x -6

x+2y-10 = 0......... is the required equation.

Hope it helps...

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2 years ago
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