Answer:
Jermey is not correct because abouslte value is always postive
Step-by-step explanation:
We want to recast the equation into the standard form equation for a circle centered at (h, k) with radius r. That equation is
... (x -h)² + (y -k)² = r²
Start by completing the square for both x-terms and y-terms.
... x² - 4x + y² + 4y = k
To do that, add the squares of half the coefficients of the x- and y-terms.
... x² - 4x + (-2)² + y² + 4y + 2² = k + (-2)² + 2²
... (x -2)² + (y +2)² = k + 8 = r² . . . . . this is now equal to the square of the radius, so we have
... k + 8 = 6² = 36
Subtracting 8 gives
... k = 28 . . . . . . . matches selection D)
Answer:Yes
Step-by-step explanation:(x-3x)=x-3
You need to write this question out in algebra form first. X + x + 1 + x + 2 = 72 than you add the like terms
3x + 3 = 72 ... 3x=69 ... x=69/3 ... x=23. So we have now found x now you just add 1 to x and get 24 and you add 2 to x you will get 25.
Add 23 + 24 + 25 together you will get 72