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Alex
3 years ago
7

Using the pencil, plot the point (-1,-5).

Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0
Just remember the negative numbers go in this coordinate problem goes in the left -1 is the x axis and -5 is the y axis. Here I set it up so that you’d understand what’s going on

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Check all the answers that are more precise than a weight of 200 grams.
Damm [24]

Answer:

amigo mío la respuesta es la letra B

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3 years ago
Which is a right triangle formed using a diagonal through the interior of the cube? A cube. The top face has points G, B, C, F a
Black_prince [1.1K]

Answer: The correct option is triangle GDC

Step-by-step explanation: Please refer to the picture attached for further details.

The dimensions give for the cube are such that the top surface has vertices GBCF while the bottom surface has vertices HADE.

A right angle can be formed in quite a number of ways since the cube has right angles on all six surfaces. However the question states that the diagonal that forms the right angle runs "through the interior."

Therefore option 1 is not correct since the diagonal formed in triangle BDH passes through two surfaces. Triangle DCB is also formed with its diagonal passing only along one of the surfaces. Triangle GHE is also formed with its diagonal running through one of the surfaces.

However, triangle GDC is formed with its diagonal passing through the interior as shown by the "zigzag" line from point G to point D. And then you have another line running from vertex D to vertex C.

6 0
3 years ago
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The height of a trapezoid is 15m and the midsegment is 32m. What is the area of the trapezoid?
viktelen [127]
The formula is: A=1/2 h (base one + base two) 

<span>Plug in your numbers and you will get the area.</span>
6 0
3 years ago
Find the 15th term in the Arithmetic Sequence An = 3n-7 Question 1 options: a32 b 7 c 38 d -2 please help
rusak2 [61]

A(15) = 3(15)-7 = 45-7 = 38.

SO, (C)38 IS THE ANSWER.

7 0
3 years ago
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21 Maria sold small boxes of candy for $1 and
Anna35 [415]

Answer:

There where 10 <u>more</u> Small boxes sold than Large boxes.

Step-by-step explanation:

<u>This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable. </u>

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable y and an Independent variable x. In a system of Two Linear equations we have<u> two equations</u> of the same variable sets (thus Two Independent variables) so in this case both y and x will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

<u>Given Information:</u>

  • Small Boxes (lets call them s) cost $1 per box
  • Large Boxes (lets call them l) cost $4 per box
  • Total Number of Boxes sold is 30
  • Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

s+l=30        Eqn(1): Total Number of Boxes

1s+4l=60     Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, s and l respectively.

From Eqn(1) we see that

s=30-l      Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for l as:

1(30-l)+4l=60

30-l+4l=60       Factored out bracket

3l=60-30          Gather similar terms on each side and simplify

3l=30

l=\frac{30}{3}

l=10

Plugging in the value for l=10 in Eqn(3) we have

s=30-10\\s=20

So we know that they were<u> 10 Large Boxes and 20 Small Boxes sold</u>, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

5 0
4 years ago
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