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pychu [463]
2 years ago
10

7. (ASV, Exercise 2.20 ) - 3 points. A fair die is rolled repeatedly. Use precise notation of probabilities of events and random

variables for the solutions to the questions below. (a) Write down a precise sum expression for the probability that the first five rolls give a three at most two times. (b) Calculate the probability that the first three does not appear before the fifth roll. (c) Calculate the probability that the first three appears before the twentieth roll but not before the fifth roll.
Mathematics
1 answer:
Korvikt [17]2 years ago
8 0

Answer:

0.9646 ; 0.5685

Step-by-step explanation:

Given that :

P(obtaining 3 on a die roll) = 1/6 = 0.1667

Obtaining 3 at most 2 times in five trials

Using binomial distribution formula :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

n = 5 ;, p = 0.1667

P(x ≤ 2) = P(x = 0) + P(x =1) + P(x = 2)

Using the binomial probability :

P(x ≤ 2) = 0.4019 + 0.4019 + 0.1608

P(x ≤ 2) = 0.9646

B.) using geometric distribution :

(1 - p)^x-1 * p

P ≥ 5) = 1 - P(x ≤ 4) = 1 - p(x = 0) + p(x = 1) + p(x =2) + p(x = 3)

1 - (0.1667 + 0.1157+0.0965+0.0804)

= 0.5685

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Combine like terms and "plug in" x into the equation to eventually get 34 after some addition
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3 years ago
How do I simplify the following to "a+bi" form: (1+2i)^3
damaskus [11]

Answer:

Expand it.

(1+2i)^3 is equal to (1+2i)(1+2i)(1+2i).

Multiply everything out (being sure to multiply <em>every</em> term. (1+2i) * (1+2i) = 1+2i+2i+4i^2.

i is the square root of negative one, so i^2 is just -1. 1+2i+2i-4 is what you get from the first two, so now simplify that:

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Step-by-step explanation:

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7 0
1 year ago
A knife is three times the cost of a spoon. 9 spoons and 12 knifes cost ?82.80 workout the cost of 1 knife.
tankabanditka [31]

Let S = spoon

Let K = knife


1 knife is thee times the cost of a spoon, so it would be 3S

Now you have 9S + 12K = 82.80

We can replace the K with 3S:

9S +12(3S) = 82.80

Simplify the left side:

9S + 36S = 82.80

Add:

45S = 82.80

Divide both sides by 45"

S = 82.80 / 45

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We know one knife cost 3 times as much, so multiply the cost of a spoon by 3:

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3 years ago
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3 0
3 years ago
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A livestock company reports that the mean weight of a group of young steers is 1143 pounds with a standard deviation of 88 pound
malfutka [58]

Answer:

<em>a) P(x<1200)=74.14%</em>

<em>b) P(1100<X<1250)=57.54%</em>

Step-by-step explanation:

<u>Normal Distribution</u>

The normal distribution, also known as the bell curve, is a distribution that occurs naturally in many situations of life. We use the model N(\mu,\sigma) to understand the behavior of some real-life variables. Where \mu is the mean value and \sigma is the standard deviation.

In our case, we have

\mu=1143,\ \sigma=88

And are required to find the percentage of steers whose weigh lie within a given range. We must use some sort of table or digital means to compute the values because the normal distribution cannot be calculated directly by a formula. We use the NORMDIST (or NORM.DIST) formula for Excel which gives us the left tail of the area behind the bell curve, i.e. the cumulative percentage for a give value of X. The formula has the form

NORM.DIST(x,mean,standard_dev,cumulative)

a) X<1200

The formula is used with the following parameters

NORM.DIST(1200,1143,88,true)

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P(X

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NORM.DIST(1100,1143,88,true)=0.3125

NORM.DIST(1250,1143,88,true)=0.8880

P(1100

\boxed{P(1100

6 0
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