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pychu [463]
3 years ago
10

7. (ASV, Exercise 2.20 ) - 3 points. A fair die is rolled repeatedly. Use precise notation of probabilities of events and random

variables for the solutions to the questions below. (a) Write down a precise sum expression for the probability that the first five rolls give a three at most two times. (b) Calculate the probability that the first three does not appear before the fifth roll. (c) Calculate the probability that the first three appears before the twentieth roll but not before the fifth roll.
Mathematics
1 answer:
Korvikt [17]3 years ago
8 0

Answer:

0.9646 ; 0.5685

Step-by-step explanation:

Given that :

P(obtaining 3 on a die roll) = 1/6 = 0.1667

Obtaining 3 at most 2 times in five trials

Using binomial distribution formula :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

n = 5 ;, p = 0.1667

P(x ≤ 2) = P(x = 0) + P(x =1) + P(x = 2)

Using the binomial probability :

P(x ≤ 2) = 0.4019 + 0.4019 + 0.1608

P(x ≤ 2) = 0.9646

B.) using geometric distribution :

(1 - p)^x-1 * p

P ≥ 5) = 1 - P(x ≤ 4) = 1 - p(x = 0) + p(x = 1) + p(x =2) + p(x = 3)

1 - (0.1667 + 0.1157+0.0965+0.0804)

= 0.5685

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Answer:

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Step-by-step explanation:

Isolate the variable of y from one side of the equation.

-14=5(3y-10)-5y

<u>First, switch sides.</u>

\sf{5\left(3y-10\right)-5y=-15}

Use the distributive property.

<u>DISTRIBUTIVE PROPERTY:</u>

A(B-C)=AB-AC

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Multiply by expand.

5*3y=15y

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15y-50-5y

15y-5=10y

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10y-50=-15

Add by 50 from both sides.

10y-50+50=-15+50

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10y=35

Then, you divide by 10 from both sides.

10y/10=35/10

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Divide the numbers from left to right.

35/10=7/2

y=7/2

Divide is another option.

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\Longrightarrow: \boxed{\sf{y=\dfrac{7}{2}}}

  • <u>Therefore, the correct answer is y=7/2.</u>

I hope this helps. Let me know if you have any questions.

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Step-by-step explanation:

Solving for variable 'x'.

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Combine like terms: 4 + -4 = 0

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