Answer:
Both flights approach each other at a speed of 624.70 Knots. The FAA minimum separation is not violated as both airplanes are 7.26 Nautical miles away from each other at the time when one of the flights( flight AA) passes through Frada Heights.
Step-by-step explanation:
To solve this kind of problem, the knowledge of concept of relative velocity is needed as the first question requested how fast the flights were approaching each other. To find the minimum distance between both flights, the closest point of approach between both flights should be taken into consideration which was Frada heights. Flight AA passes through Frada Heights in a shorter time of 0.079 hours. This is the time at which both flights approach each other the closest and so the minimum distance (separation) between them. This was calculated to be 7.26NM which is greater than the FAA's minimum this requirement for flight was not violated.
Detailed calculation steps can be found in the attachment below.
Answer:
The y-intercept is (0, 13).
Step-by-step explanation:
First finf the equation of the line:
The slope = (25- 5) / (3 - -2)
= 20/5
= 4
So its equation is
y - 5 = 4(x + 2)
y = 4x + 13
The y-intercept occurs when x = 0
so y-intercept = 4(0) + 13.
It's (0, 13).
Answer:
8.D
9.A
Step-by-step explanation:
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Answer:
MNK = TRP
MN is congruent to TR.
X = 6.3
Step-by-step explanation:
MNK is congruent to TRP because the two triangles are congruent, which is a given statement. This also means that all side and angle measures will be congruent. Because of this, it can be inferred that MN is congruent to TR and they have equal side length measures. This means that TR measures 20. This means that 3X - 1 = 20. By solving we can get 6.33.