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Grace [21]
3 years ago
5

13 mins left oh gees oh gosh

Mathematics
1 answer:
gavmur [86]3 years ago
7 0

Answer:

I think that it is a quadratic

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Add all of the side lengths together.
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The general form of a circle is given as x^2+y^2+4x - 12y + 4 = 0. A) What are the coordinates of the center of the circle? B) W
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Answer:

center = (-2, 6)

radius = 6

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

(where (a, b) is the center and r is the radius)

Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.

Given equation:

x^2+y^2+4x-12y+4=0

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\implies x^2+4x+\left(\dfrac{4}{2}\right)^2+y^2-12y+\left(\dfrac{-12}{2}\right)^2=-4+\left(\dfrac{4}{2}\right)^2+\left(\dfrac{-12}{2}\right)^2

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Factor both variables:

\implies (x+2)^2+(y-6)^2=36

Therefore:

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Use the intersect method to solve the equation x^2-1=-x^2+7
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Answer:

The solutions of the equation x^2-1=-x^2+7 are (-2,3) and (2,3)

Step-by-step explanation:

Please, see the attached file.

Thanks.

4 0
3 years ago
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