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jeka94
3 years ago
5

A traffic camera sits on top of a tower that has a height of 39 ft. The angles of depression of a car on a straight road at the

same level as that of the base of the tower and on the same side of the tower are 31°. Calculate the the distance between the base of the poll and the car. Round to the nearest tenth of a foot. *
Mathematics
1 answer:
MrMuchimi3 years ago
7 0

Answer:

48ft

Step-by-step explanation:

  • <u>Distance of car A from the tower</u>
  • Consider ∆ACD tan25 = 50/AC AC  = 50/tan25 = 50/0.4663 = 107.2 ft
  • <u>Distance of car B from the tower</u>
  • Consider ∆BCD tan40 = 50/BC AC  = 50/tan40 = 50/0.8391 = 59.6 ft

  • <u>Distance from cars A and B</u> AB = AC – BC = 107.2 – 59.6 = 48 ft The distance between the two cars is 48ft
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t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{1.307 -0}{\frac{7.798}{\sqrt{14}}}=0.6271

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Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

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The system of hypothesis for this case are:

Null hypothesis: \mu_x- \mu_y \leq 0

Alternative hypothesis: \mu_x -\mu_y >0

The first step is calculate the difference d_i=x_i-y_i and we obtain this:

d: 13.1, -16.4,-5.7,4.1,3.9,5.2,5.9,2.8,1.6,-2.7,-0.6,11.7,-8.7,4.1

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The third step would be calculate the standard deviation for the differences, and we got:

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