Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
(
) & (
)-
y -
=
( x -
)
i.e. <em> y - 7=
( x- 1)</em>
<em> y - 7 =
( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.
Answer:
![\displaystyle m^{\frac{35}{12}}n^{-\frac{28}{15}}=\frac{m^{\frac{35}{12}}}{n^{\frac{28}{15}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20m%5E%7B%5Cfrac%7B35%7D%7B12%7D%7Dn%5E%7B-%5Cfrac%7B28%7D%7B15%7D%7D%3D%5Cfrac%7Bm%5E%7B%5Cfrac%7B35%7D%7B12%7D%7D%7D%7Bn%5E%7B%5Cfrac%7B28%7D%7B15%7D%7D%7D)
Step-by-step explanation:
The relevant rule of exponents is ...
(a^b·c^d)^e = a^(be)·c^(de)
Then ...
(m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)
= m^(35/12)·n^(-28/15)
__
Since you want positive rational exponents, you can write this as ...
= m^(35/12)/n^(28/15)
Answer:
It takes 2.8 seconds for the ball to fall 215 ft.
Step-by-step explanation:
We are given a position function s(t) where s stands for the number of feet the ball has fallen, so we have to replace s with the given value of 215 ft and solve for the time t.
Setting up the equation.
The motion equation is given by
![s(t) =16t^2+32t](https://tex.z-dn.net/?f=s%28t%29%20%3D16t%5E2%2B32t)
We can replace there s = 215 ft to get
![215=16t^2+32t](https://tex.z-dn.net/?f=215%3D16t%5E2%2B32t)
Solving for the time t.
From the previous equation we can move all terms in one side to get
![16t^2+32t-215=0](https://tex.z-dn.net/?f=16t%5E2%2B32t-215%3D0)
At this point we can solve for t using quadratic formula.
![t = \cfrac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=t%20%3D%20%5Ccfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
where a, b and c are the coefficients of the quadratic equation
![at^2+bt+c=0](https://tex.z-dn.net/?f=at%5E2%2Bbt%2Bc%3D0)
So we get
![a=16\\b=32\\c=-215](https://tex.z-dn.net/?f=a%3D16%5C%5Cb%3D32%5C%5Cc%3D-215)
Replacing on the quadratic formula we get
![t = \cfrac{-32\pm \sqrt{32^2-4(16)(-215)}}{2(16)}](https://tex.z-dn.net/?f=t%20%3D%20%5Ccfrac%7B-32%5Cpm%20%5Csqrt%7B32%5E2-4%2816%29%28-215%29%7D%7D%7B2%2816%29%7D)
Using a calculator we get
![t=-4.8 , t = 2.8](https://tex.z-dn.net/?f=t%3D-4.8%20%2C%20t%20%3D%202.8)
Physically speaking the only result that makes sense is to move forward in time that give us t = 2.8 seconds.
We can conclude that it takes 2.8 seconds for the ball to fall 215 ft.
Answer:
Joe Mama :))))))))))))))))))))))
Step-by-step explanation:
9514 1404 393
Answer:
1.49283
Step-by-step explanation:
8.1% as a decimal is 0.081
The product of that and 18.43 is ...
0.081 × 18.43 = 1.49283
__
If this is a monetary value, it would round to 1.49.