Solve for x e^2x=2.6
1 answer:
You might be interested in
Without using the trigonometry ratio, we can find the distance between the ship and the buoy by:
the distance between City and Lemont SUBTRACT the vertical distance between City and the point parallel to the Ship
The distance between the City and Lemont can be worked out using the Sin rule
≈98.3
The vertical distance between the City and the point parallel to the ship can be worked out using the Pythagoras theorem
≈36.8
The distance between the ship and the Buoy is given:
miles
the distance between City and Lemont SUBTRACT the vertical distance between City and the point parallel to the Ship
The distance between the City and Lemont can be worked out using the Sin rule
The vertical distance between the City and the point parallel to the ship can be worked out using the Pythagoras theorem
The distance between the ship and the Buoy is given:
Using the normal distribution, we have that:
a) The probability of a student scoring less than 19 is 0.2709 = 27.09%.
b) The probability of a student scoring between 17.7 and 27.1 is 0.6424 = 64.24%.
c) The probability of a student scoring more than 33.1 is 0.0179 = 1.79%.
d) The correct option is: B. The event in part (c) is unusual because its probability is less than 0.05.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
Item a:
The probability is the <u>p-value of Z when X = 19</u>, hence:
Z = -0.67.
Z = -0.67 has a p-value of 0.2709.
The probability of a student scoring less than 19 is 0.2709 = 27.09%.
Item b:
The probability is the <u>p-value of Z when X = 27.1 subtracted by the p-value of Z when X = 17.7</u>, hence:
X = 27.1:
Z = 0.92.
Z = 0.92 has a p-value of 0.8212.
X = 17.7:
Z = -0.92.
Z = -0.92 has a p-value of 0.1788.
0.8212 - 0.1788 = 0.6424.
The probability of a student scoring between 17.7 and 27.1 is 0.6424 = 64.24%.
Item c:
The probability is <u>one subtracted by the p-value of Z when X = 33.1</u>, hence:
Z = 2.1.
Z = 2.1 has a p-value of 0.9821.
1 - 0.9821 = 0.0179.
The probability of a student scoring more than 33.1 is 0.0179 = 1.79%.
Item d:
Probabilities less than 0.05 are unusual, hence the correct option is:
B. The event in part (c) is unusual because its probability is less than 0.05.
More can be learned about the normal distribution at brainly.com/question/28135235
#SPJ1