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ira [324]
3 years ago
10

Solve for x e^2x=2.6

Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0

Answer:

Solve for

x

x

by simplifying both sides of the equation, then isolating the variable.

x

≈

0.25181781

Step-by-step explanation:

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27- 2b greater or equal to - 6
dezoksy [38]
27-2b > -6
-2b > -6-27
-2b > -33
b < -33/-2 (you have to change the sign when you divide with a negative number)
b < 16.5
(all the signs are supposed to have a line under them to make them greater or equal or less than or equal to)
5 0
3 years ago
I need help with the attached​
Aleksandr-060686 [28]

Answer: super sorry! i have no idea but im sure someone else knows (:

Step-by-step explanation:

sorry

8 0
2 years ago
What is the halflife
blagie [28]
To model half-life, use the formula A(t)=A_0 (\dfrac{1}{2})^{ \frac{t}{t_{1/2}}. Here, A(t) is the amount remaining after a length of time t. A_0 is the amount that you start with. t_{1/2} is the half-life. You plug in 50 for t_{1/2}, 10 for A_0, and 25 for t. You get A(t)=10( \frac{1}{2})^{25/50} = 10( \frac{1}{2})^{1/2} = 7.07 \ grams.
5 0
3 years ago
Rewrite In simplest radical form x^5/6/x^1/6
Nady [450]
I assume you mean:

[x^(5/6)]/[x^(1/6)]

The rule for dividing similar bases with different exponents is:

(a^b)/(a^c)=a^(b-c)

In this case we have:

x^(5/6-1/6)

x^(4/6)

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3 0
3 years ago
Help please!!!! Asap!! math whizzes!!!
Katyanochek1 [597]

Answer:

5xy^3 \sqrt{3x}

Step-by-step explanation:

The radical \sqrt{75x^3y^6} can be simplified by breaking it down into factors and removing the perfect squares from inside the radical.

\sqrt{75x^3y^6} =\sqrt{3*25*x^2*x*y^6} =5xy^3 \sqrt{3x}

25 is a perfect square and is 5 outside the radical.

x^2 is a perfect square and is x outside the radical.

y^6 is a perfect square and is y^3 outside the radical.

7 0
3 years ago
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