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maksim [4K]
3 years ago
9

Prove that these equations are equivalent a/b=c/d

Mathematics
1 answer:
zvonat [6]3 years ago
8 0

Answer:

How am I supposed to answer this? are there any answer choices or an equation im supposed to look at ?

Step-by-step explanation:

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Which of the following statements is true?
Semmy [17]

Answer:

Option B

Step-by-step explanation:

we know that

A <u>rational number</u> is one that can be represented as the ratio of two whole numbers

so

\frac{\sqrt{5}}{8} -----> Is not a rational number, because √5 is not a whole number, is a irrational number

\frac{\sqrt{4}}{9}=\frac{2}{9} ---> Is a rational number, because can be represented as the ratio of two whole numbers

therefore

√5/8 is irrational and √4/9 is rational

7 0
4 years ago
Given f of x is equal to 1 over the quantity x minus 3 end quantity and g of x is equal to the square root of the quantity x plu
Lostsunrise [7]

The domain of the composite function is given as follows:

[–3, 6) ∪ (6, ∞)

<h3>What is the composite function of f(x) and g(x)?</h3>

The composite function of f(x) and g(x) is given as follows:

(f \circ g)(x) = f(g(x))

In this problem, the functions are:

  • f(x) = \frac{1}{x - 3}.
  • g(x) = \sqrt{x + 3}

The composite function is of the given functions f(x) and g(x) is:

f(g(x)) = f(\sqrt{x + 3}) = \frac{1}{\sqrt{x + 3} - 3}

The square root has to be non-negative, hence the restriction relative to the square root is found as follows:

x + 3 \geq 0

x \geq -3

The denominator cannot be zero, hence the restriction relative to the denominator is found as follows:

\sqrt{x + 3} - 3 \neq 0

\sqrt{x + 3} \neq 3

(\sqrt{x + 3})^2 \neq 3^2

x + 3 \neq 9

x \neq 6

Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the domain is:

[–3, 6) ∪ (6, ∞)

More can be learned about composite functions at brainly.com/question/13502804

#SPJ1

7 0
2 years ago
A gallon can of paint holds 8 pints. The label says it will cover 400 square feet.
iren [92.7K]
I think it is B. 50 feet
6 0
3 years ago
Read 2 more answers
Can anyone help me!?!?!?!?! Here is my question:
Maslowich
The sine function has a minimum value of -1, so f(x) = 4sin( ) -1 will have a minimum value of -5.

g(x) obviously has a minimum value of -3.

h(x) has a squared term that cannot be negative, so its minimum value is +4.


f(x) has the smallest minimum value.

8 0
3 years ago
Compare, in the box below, 0.5 and 0.5 when written as fractions. Make an observation about these repeating decimals when they a
lord [1]
5/10 & 5/10
The zero just repeats.
3 0
3 years ago
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