Marcus and Cody both leave the park at the same time, but in opposite directions. If Cody travels 6 mph faster than Marcus and a fter 4 hours they are 64 miles apart, how fast is each traveling? Solve using Rare times time = Distance.
1 answer:
Answer: Marcus travels at 5mph and Cody travels at 11mph
Step-by-step explanation:
x = Marcus
x + 6 = Cody
4(x + x + 6) = 64
4x + 4x + 24 = 64
8x + 24 = 64
8x = 40
40/8 = 5
5 + 6 = 11
Marcus = 5 Cody = 11
4*5 + 11*4 = 64
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