If x + 5y = -11 and 2x − 3y = 17, what is the value of x + y?

Mathematics

1 answer:

aev [14]3 years ago

6 0

X+5y=-11 (1)
2x-3y=17 (2)

2(1)-(2)
2x+10y-2x+3y=-22-17
13y=-39
y=-3

Sub y=-3 in (1)
x+5(-3)=-11
x=4

So x+y= -3+4 =1

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The daily dinner bills in a local restaurant are normally distributed with a mean of $28 and a standard deviation of $6. What ar

Degger [83]

Answer:

The minimum value of the bill that is greater than 95% of the bills is $37.87.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 28, \sigma = 6$