i need help solving the bottom part and filling the letters in the teacher said some spaces and supposed to be blank

"The fitted regression line will always run through the mean of the observed data. In other words, the point (x with bar on top,

Kamila [148]

Great question goodluck in the future

6 0

3 years ago

In art class tico is copying a detail from a painting

Triss [41]

An apple
a pear
a bannana

7 0

3 years ago

Read 2 more answers

What is the equation of the line that is parallel to y=3x+2 and goes through the points (5,8)?

ira [324]

Parallel lines has equal slopes.

Line y = 3x + 2 has a slope of 3.

Required equation is y - 8 = 3(x - 5)
y = 3x - 15 + 8
y = 3x - 7

6 0

3 years ago

How many different triangles can you make with 14cm, 10cm and 50cm sides?

vovangra [49]

Answer:

You can make NO triangles.

When given 3 sides of a triangle, The longest side must be LESS than the sum of the other 2 sides.

Longest Side = 50 cm

50 is NOT less than 14 + 10, therefore, we have no triangle.

Step-by-step explanation:

8 0

3 years ago

Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3>Given :-</h3>

The right angled below is formed by 3 squares A, B and C
The area of square B has an area of 144 inches ²
The area of square C has an of 169 inches ²

We have to find the area of square A?

<h3>Let's Begin :- </h3>

The right angled triangle is formed by 3 squares

We have, 

Area of square B is 144 inches²
Area of square C is 169 inches²

We know that,

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

Subsitute the required values,

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

Area of square C = 169 inches

Let the side of square C be y

Subsitute the required values,

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3>Therefore, By using Pythagoras theorem, </h3>

The sum of squares of base and perpendicular height equal to the square of hypotenuse

That is,

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

Here, 

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

Subsitute the required values,

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3>Therefore,</h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

6 0

2 years ago

i need help solving the bottom part and filling the letters in the teacher said some spaces and supposed to be blank ​

i need help solving the bottom part and filling the letters in the teacher said some spaces and supposed to be blank