Here we are given the three sides of the triangle.
So we have Heron's formula to find its area.
Heron's formula is given by :
where A, B and C are sides of triangle and S is semi perimeter which is given by,
plugging values of A, B and C to find S
S=13.5
Now plugging values of A, B , C and S in Heron's formula
A=26.14 mm²
Answer: Area of triangle is 26.14 mm².
Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
