i need help solving the bottom part and filling the letters in the teacher said some spaces and supposed to be blank

algol [13]

Answer: $\displaystyle\\\frac{2\pi }{3},\ \frac{5\pi }{3} .$

Step-by-step explanation:

$\displaystyle\\tan\theta=-\sqrt{3}\ \ \ \ 0\leq \theta\leq 2\pi \\\theta =\frac{2\pi }{3}+\pi N\ \ \ (N=0,\ 1,\ 2,\ 3\ ...)\\ N=0\\\theta=\frac{2\pi }{3} +\pi *0\\\theta=\frac{2\pi }{3}\ \ \ \ ( 0\leq \theta\leq 2\pi)\\ N=1\\\theta=\frac{2\pi }{3}+\pi *1 \\\theta=\frac{2\pi }{3} +\pi \\\theta=\frac{2\pi +3\pi }{3} \\\theta=\frac{5\pi }{3} \ \ \ ( 0\leq \theta\leq 2\pi)\\$

$N=2\\\theta=\frac{2\pi }{3}+2\pi \\ \theta=\frac{2\pi +3*2\pi }{3}\\ \theta=\frac{2\pi +6\pi }{3} \\\theta=\frac{8\pi }{3} \\\theta=2\frac{2}{3} \pi \ \ \ \ (\notin0\leq \theta\leq 2\pi).\\$

6 0

1 year ago

Please help as soon as possible

Luda [366]

EQUATION 1: x-y=12
EQUATION 2: 3x+y=4

STEP 1:
solve for one variable in equation 1

x - y= 12
add y to both sides

x= 12 + y

STEP 2:
use x value from step 1 and substitute in equation 2

3x + y= 4

3(12 + y) + y= 4
multiply 3 by parentheses

(3*12) + (3*y) + y= 4
multiply inside parentheses

36 + 3y + y= 4
combine like terms

36 + 4y= 4
subtract 36 from both sides

4y= -32
divide both sides by 4

y= -8

STEP 3:
substitute y value from step 2 into either equation

x - y= 12
x - (-8)= 12
x + 8= 12
subtract 8 from both sides
x= 4

CHECK:
x= 4, y= -8

3x + y= 4
3(4) + (-8)= 4
12 - 8= 4
4= 4

ANSWER: The x value is 4 and the y value is -8.

Hope this helps! :)

5 0

4 years ago

What is the mean absolute deviation of attendance at the 4 middle school dances?

Mice21 [21]

Answer:

Hope this helps you to understand, to do the problem and for future problems!

Step-by-step explanation:

All you have to do is take the numbers, add them, then divide them by how much there are. Once you did that if its a negative you just turn it positive bc its absolute.

4 0

3 years ago

The function A(b) relates the area of a trapezoid with a given height of 10 and

Natali [406]

Answer:

$B(a)=\frac{a}{5} -7$

Step-by-step explanation:

The input it taken as the unknown base value, while the output here is the area of the trapezoid. b is therefore the base value, and A( b ) is the area of the trapezoid. Let's formulate the equation for the area of the trapezoid, and isolate the area of the trapezoid. To find the inverse of this function, switch y ( this is A( b ) ) and b, solving for y once more, y ➡ y ⁻ ¹.

y = height $*$ ( ( unknown base value ( b ) + 7 ) / 2 ),

y = 10 $*$ ( ( b + 7 ) / 2 )

Now switch the positions of y and b -

b = 10 $*$ ( ( y + 7 ) / 2 ) or $b=\frac{\left(y+7\right)\cdot \:10}{2}$ - now that we are going to take the inverse ( y ⁻ ¹ ) or B( a ), b will now be changed to a,