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sesenic [268]
3 years ago
12

Find the GCF of each pair of terms.

Mathematics
2 answers:
alukav5142 [94]3 years ago
6 0

Answer:

A = 4, B = 5, C = 2, D = 14

Step-by-step explanation:

kozerog [31]3 years ago
3 0
1. 4(1, 4)
2. 5(4, 13)
3. 2(x, 2)
4. 14x(y, 3)
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How to calculate the rise and run of a slope (4,-1) and (-2,3)
astra-53 [7]
m =  \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }
m =   \frac{3 - (-1)}{-2 - 4}
m =  \frac{4}{2}
m = 2
8 0
3 years ago
Bill wants to rent a car.Rental Company A charges $35 per day plus $0.10 per mile driven.Rental Company B charges $25 per day pl
zlopas [31]

Answer:

m = 200 miles

Step-by-step explanation:

Rental Co. A:  A(m) = $35 + ($0.10/mile)(m), where m is the number of miles driven

Rental Co. B:  B(m) = $25 + ($0.15/mile)(m)

Set these two dollar amounts equal to each other and solve for m:

$25 + ($0.15/mile)m = $35 + ($0.10/mile)(m).  Combine like terms, obtaining:

($0.05/mile)m = $10; then m = ($10) / ($0.05/mile), or 200 miles.

The price charged by the two companies would be the same when the car has been driven 200 miles.

7 0
3 years ago
how to solve this prroblem by marianne buys 16 bags of potting soil that come in 5÷8_pound bags .how many pounds of potting soil
barxatty [35]
So, she buys 16 bags, each of them weights\frac{5}{8} pounds.

to find how many pounds of soil she bought, we have to multiply:

16*\frac{5}{8}=//16 is equal to 8*2, so we can simpify:
2*\frac{5}{1}

which is 2*5=10

so in the end she bought 10 pounds of soil!

3 0
3 years ago
A researcher conducts an experiment comparing two treatment conditions with 20 scores in each treatment condition.
Savatey [412]
To determine the number of subjects that are needed for the experiments, we multiply the number of independent variables with the number of scores. For example, there are n independent variables then, there are approximately,

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6 0
3 years ago
Plzzz help plzzzzzzzzzzzzzz
mezya [45]

Given:

The figure of two quadrilaterals.

In ABCD,AB=18,BC=20,CD=22,AD=24

In EFGH,EF=27,FG=30,GH=34, EH=36

To find:

Whether the figures are congruent, similar or neither.

Solution:

Ratio of corresponding sides are:

\dfrac{AB}{EF}=\dfrac{18}{27}

\dfrac{AB}{EF}=\dfrac{2}{3}

Similarly,

\dfrac{BC}{FG}=\dfrac{20}{30}

\dfrac{BC}{FG}=\dfrac{2}{3}

\dfrac{CD}{GH}=\dfrac{22}{34}

\dfrac{CD}{GH}=\dfrac{11}{17}

And,

\dfrac{AD}{EH}=\dfrac{24}{36}

\dfrac{AD}{EH}=\dfrac{2}{3}

Clearly, \dfrac{AB}{EF}=\dfrac{BC}{FG}=\dfrac{AD}{EH}\neq \dfrac{CD}{GH}.

All corresponding sides are not proportional.

Therefore, the figures are neither similar nor congruent. Hence, third option is correct.

7 0
3 years ago
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