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kap26 [50]
2 years ago
6

magine you have two friends, Jose and Jessie. Jose is a gifted athlete, but Jessie lives a sedentary lifestyle. Jose and Jessie

both ask you to develop an action plan to improve their flexibility. How would your advice differ for Jose and Jessie? Consider specific exercises, frequency of exercise, level of conditioning, levels of flexibility, goal setting, and other important factors in your response.
Mathematics
2 answers:
GuDViN [60]2 years ago
7 0

Answer:

First of all, Jose and Jessie have a big difference when it comes to physical health and condition. Jessie is not able to perform the same exercises as Jose, neither the same intensity, and they cannot have the same goal.

So, for Jessie improve her flexibility we have to consider low intensity exercises, specifically, aerobic exercises, like walking, dancing, jogging at a low pace, pilates and yoga. Jessie, as a sedentary person most consider to do those aerobic activities three times per week, at least 30 minutes to ensure that she is demanding enough effort from her body, but all at low intensity.

Step-by-step explanation:

ryzh [129]2 years ago
4 0
Advice for Jose is to start to work-on a more advance level of flexibility such as Knee to chest, side lungs, seat side straddle and more. Advice for Jessie would be to start with the safety doing stretches, perform simple warmups and experiment on doing the spits.
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Answer:

Variable rate of change.

Step-by-step explanation:

Plot the points and you'll see that the graph is not a straight line, therefore the rate of change is variable.

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2 years ago
Suppose j varies jointly with g and​ v, and j=2 when g=4 and v=3. <br> Find j when g=8 and v=9.
vladimir2022 [97]

Answer:

j=12

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form j = kgv

where k is a constant

step 1

Find the value of k

we have

j=2,g=4,v=3

substitute and solve for k

2 = k(4)(3)

2 = 12k

k=\frac{1}{6}

The equation is equal to

j=\frac{1}{6}gv

step 2

Find the value of j when g=8,v=9

substitute the values in the equation and solve for j

j=\frac{1}{6}(8)(9)

j=12

3 0
3 years ago
Determine mode and median​
saveliy_v [14]
Mode is the total average median is the middle number
7 0
2 years ago
Read 2 more answers
Part of the graph of the function f(x) = (x – 1)(x + 7) is shown below.Which statements about the function are true? Select thre
sertanlavr [38]

The statements about the function that are true are

  • The vertex of the function is at (–3,–16).
  • The graph is increasing on the interval x > –3.
  • The graph is positive only on the intervals where x < –7 and where x > 1.

<h3>How to interpret the graph?</h3>

The equation of the graph is given as

f(x) = (x - 1)(x + 7)

The graph of the function is added as an attachment

On the graph, we have

Vertex = (-3, -16)

This is so because the graph has a minimum point of (-3, -16)

Also, the graph crosses the x-axis at x = 1 and x = -7

This means that the graph is positive at x >1 and x >-7

Because the vertex is a minimum, the graph is increasing at the left of its symmetry i.e. x > -3

Read more about quadratic functions at

brainly.com/question/14933288

#SPJ1

7 0
1 year ago
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =
BabaBlast [244]

Answer:

4c² + 11cd + 5d

Step-by-step explanation:

(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)

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8c²-4c²+7cd + 4cd + 8d - 3d

= 4c² + 11cd + 5d

4 0
2 years ago
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