Answer:
fgscgethre 4 fsvcadc 14143
Step-by-step explanation:
i just tryna get point lol srry
A square is a square a trapezoid is a lot weirder <span />
Given equation is
The given equation is in the form of
a^2= 16 , so a=4
b^2 = 9 so b= 4
The value of 'a' is greater than the value of 'b'
So it is a Horizontal hyperbola
First two graphs are horizontal hyperbola
Here center is (h,k)
h= 5 and k =2 from the given equation
So center is (5,2)
Now we find vertices
Vertices are (h+a,k) and (h-a,k)
We know h=5, k=2 and a=4
So vertices are (9,2) and (1,2)
Second graph having same vertices and center
The correct graph is attached below
Answer:
20%
Step-by-step explanation:
Write the problem as a mathematical expression.
63/315
Convert to decimal
0.2
Times by 100
0.2 times 100
20%