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Sveta_85 [38]
2 years ago
15

Assume that theta is a positive acute angle.

Mathematics
1 answer:
muminat2 years ago
6 0

Answer:

Step-by-step explanation:sin

(

θ

)

=

40

41

Use the definition of sine to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values.

sin

(

θ

)

=

opposite

hypotenuse

Find the adjacent side of the unit circle triangle. Since the hypotenuse and opposite sides are known, use the Pythagorean theorem to find the remaining side.

Adjacent

=

√

hypotenuse

2

−

opposite

2

Replace the known values in the equation.

Adjacent

=

√

(

41

)

2

−

(

40

)

2

Simplify

√

(

41

)

2

−

(

40

)

2

.

Tap for more steps...

Adjacent

=

9

Find the value of cosine.

Tap for more steps...

cos

(

θ

)

=

9

41

Find the value of tangent.

Tap for more steps...

tan

(

θ

)

=

40

9

Find the value of cotangent.

Tap for more steps...

cot

(

θ

)

=

9

40

Find the value of secant.

Tap for more steps...

sec

(

θ

)

=

41

9

Find the value of cosecant.

Tap for more steps...

csc

(

θ

)

=

41

40

This is the solution to each trig value.

sin

(

θ

)

=

40

41

cos

(

θ

)

=

9

41

tan

(

θ

)

=

40

9

cot

(

θ

)

=

9

40

sec

(

θ

)

=

41

9

csc

(

θ

)

=

41

40

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Step-by-step explanation:

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5 0
3 years ago
Use the following triangle to find Sec theta.
makkiz [27]

Answer:

\frac{\sqrt{41}}{4}

Step-by-step explanation:

sec(theta) is defined as: sec(\theta)=\frac{1}{cos(\theta)} = \frac{hypotenuse}{adjacent}

In the diagram you provided the hypotenuse of the triangle is sqrt(41) and the opposite side is 5, using these two sides, we can solve for the adjacent side by using the Pythagorean Theorem: a^2+b^2=c^2

So this gives us the equation where a=adjacent side:

a^2+5^2=\sqrt{41}^2

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Subtract 25 from both sides

a^2=16

Take the square root of both sides

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