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mel-nik [20]
3 years ago
9

Jake went on a road trip with his family this summer. On Monday, they drove 629 miles. Tuesday, they drove 215 miles. On Wednesd

ay, they only drove 111 miles. And, on Thursday, they drove 588 miles. What is the total number of miles that Jake's family traveled?
Mathematics
1 answer:
kvv77 [185]3 years ago
6 0

Answer:

1543 miles

Step-by-step explanation:

629 + 215 + 111 + 588 = 1543

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3 years ago
David roller skates with a constant speed of 12kmh how far can he travel in 3 hours
Leona [35]

Answer:

36

Step-by-step explanation:

12 x 3 =36

6 0
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I literally don’t get this I need the answer
Ksju [112]

Answer:

62.83 units^{3}

Step-by-step explanation:

The equation is V(Volume) equals π (Pi/3.14) multiplied by r(radius) squared multiplied by h(height). The way it would be written out is V=π×r^{2}×h. So when you plug in the radius (2) and the height (5) you get π×2^{2}×5 which equals 62.83185 or 62.83. I hope this helps you understand and if you need more help let me know.

6 0
2 years ago
If you vertically compress the absolute value parent function ?? What is the equation of the new function
Bumek [7]

Answer: Choice A -- f(x) = (1/3)*|x|

============================================

The input of a function is x and the output is y = f(x)

To vertically compress a function, we will multiply the y value by some fraction smaller than 1. This is so that the y coordinates are a fraction of what they once were.

In this case, we multiply y by 1/3 so that something that has a y coordinate of y = 81 becomes y = 27 (divide by 3)

So we have y = f(x) become (1/3)*y = (1/3)*f(x) = (1/3)*|x|

4 0
3 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
3 years ago
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