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Mashutka [201]
2 years ago
7

Help I have a C in math. I don't understand this Alegbra. If you get it right then I will give you Brainlist!

Mathematics
1 answer:
I am Lyosha [343]2 years ago
6 0

irrational number, any real number that cannot be expressed as the quotient of two integers.

Any number that can be written as a fraction with integers is called a rational number . For example, 17 and −34 are rational numbers. (Note that there is more than one way to write the same rational number as a ratio of integers.

1st Is rational

2nd one is irrational

3rd is irrational

4th is rational

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Sams dog weighs 72 pounds. the vet suggest that for the dogs health, its weight should decrease by 12.5 percent . According to t
Sophie [7]
The healthy weight for the dog is around 64 lbs
3 0
3 years ago
HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!
aksik [14]
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)








7 0
3 years ago
When the sum of a number and 14 is<br> divided by 3, the result is 4.
kvv77 [185]

Answer:

it is 4.6 sorry girl

Step-by-step explanation:

5 0
3 years ago
I need a answer to 77.5% of 13.270​
den301095 [7]

Answer:

10.28425

Step-by-step explanation:

4 0
3 years ago
Can someone help me with this
Dmitrij [34]

Answer:

\frac{1}{18}

Step-by-step explanation:

So say there are x yellow cubes.

Yellow = x

Blue = 3x

Green = 15x

It doesn't say red so I'm going to assume there are none.

\frac{x}{18x}=\frac{1}{18}

7 0
3 years ago
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