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Ronch [10]
3 years ago
10

Why is it important to break up any lumps in baking soda before you place vinegar or water in it?

Chemistry
2 answers:
Eddi Din [679]3 years ago
6 0

It is important to break up the lumps of baking soda before you put it into the vinegar or water because the powder will mix more easily.

Tems11 [23]3 years ago
3 0
It will mix more easily
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The maximum number of electrons in a p-sublevel is: 2 6 1 10 14
Mashcka [7]
P orbitals have 3 sub-shells, each of which can hold one pair of electrons that have opposing spins. This leads to p orbitals holding a maximum of 6 electrons
3 0
3 years ago
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You are given three liquids. You know that one of them is a suspension, one is a solution with nonelectrolytes, and the other is
Aleks [24]

Answer:

decant/ filter then decompose the electrolytes by electrolysis

Explanation:

4 0
3 years ago
A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then b
lilavasa [31]

The given question is incomplete. The complete question is as follows.

A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then bringing the volume up to 1.000 l. it was determined that the volume of water needed to do this was 999.4 ml . the density of water at 20.0∘c is 0.9982 g/ml.

Calculate the molality of the salt solution.

Express your answer to four significant figures and include the appropriate units.

Explanation:

Molality is defined as the number of moles present in kg of a solvent.

Mathematically,     Molality = \frac{\text{moles of solute}}{\text{mass of solvent}}

Also,

      Mole of solute = Molarity of solute x Volume of solution

                               = (0.0230 M) x (1.000 L) = 0.0230 mol of solute

Therefore, mass of solvent will be as follows.

     999.4 mL \times (\frac{0.9983 g}{1 mL})

                  = 997.7 g

                  = 0.9977 kg        (as 1 kg = 1000 g)

Therefore, we will calculate the molality as follows.

          Molality = \frac{0.0230 mol}{0.9977 kg}

                   = 0.02306 mol/kg

thus, we can conclude that molality of the given solution is 0.02306 mol/kg.

8 0
3 years ago
PLEASE ANSWER I NEED THE ANSWER ASAP!!!!!!!!!The table shows the amount of radioactive element remaining in a sample over a peri
qaws [65]

Answer:

pt1

The half-life of the element is 1,600 years.

pt2

k = ln(2)/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(1,600 years) = 4.33 x 10⁻⁴ year⁻¹.

kt = ln([A₀]/[A]),

where, k is the rate constant of the reaction (k = 4.33 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of the sample ([A₀] = 312.0 g).

[A] is the remaining concentration of the sample ([A] = 9.75 g).

∴ t = (1/k) ln([A₀]/[A]) = (1/4.33 x 10⁻⁴ year⁻¹) ln(312.0 g/9.75 g) = [8,000 year].

-Hops

3 0
4 years ago
If 0.0987 g H2O hydrolyzes, what is the theoretical yield of H2? 2H2O → → 2H2 + O2
Pavlova-9 [17]

The theoretical yield is 0.0110 g H₂.

<em>Moles of H₂O</em> = 0.0987 g H₂O × (1 mol H₂O/18.02 g H₂O) = 0.005 477 mol H₂O

<em>Moles of H₂</em> = 0.005 477 mol H₂O × (2 mol H₂/2 mol H₂O) = 0.005 477 mol H₂

<em>Theoretical yield</em> of H₂ = 0.005 477 mol H₂ × (2.016 g H₂/1 mol H₂)

= 0.0110 g H₂

4 0
3 years ago
Read 2 more answers
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