The ostrich can run 20 miles in 40 minutes.
<u>Solution:</u>
Given that, An ostrich run 6 mile in 12 minutes
We have to find how far he could come in 40 minutes
Now, according to the given information
Ostrich runs 6 miles ⇒ 12 minutes
Then, “n” miles ⇒ 40 minutes
Now, by criss cross multiplication we get,

Hence, the ostrich can run 20 miles in 40 minutes
Answer:This problem is about linear equations. We assume Dale drive X miles, and the total cost is $Y, then we can get:
Plan I: Y=38+0.11X
Plan II: Y=49+0.07X
When both plans cost the same, 38+0.11X=49+0.07X. We will get X = 275miles, and Y=$68.25
Step-by-step explanation:
Answer:
Both are rational.
Step-by-step explanation:
As a rational number can be written in the form p/q where p,q are co-prime integers, let a=p1/q1 b=p2/q2.
And we know the product of two integers is an integer
p1q2, p2q1 are integers. And the sum or difference of two integers is rational, rather being specific, it is an integer.
Thus a+b and a-b is rational.
Answer:
11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Forecast of rain.
Event B: Raining.
In recent years, it has rained only 5 days each year.
A year has 365 days. So

When it actually rains, the weatherman correctly forecasts rain 90% of the time.
This means that 
Probability of forecast of rain:
90% of 0.0137(forecast and rains)
10% of 1 - 0.0137 = 0.9863(forecast, but does not rain)

What is the probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain