What are the explicit equation and domain for a geometric sequence with a first term of 2 and a second term of −8?
1 answer:
The common ratio in a geometric sequence is the ratio between 2 consecutive terms:
-8/2=-4,
then the sequence is 2, -8, 32, -128, -512, 2048, ...
let
be the nth term of the sequence, then
.
.
.
so clearly
and, clearly n are integers >0, since we have a 1st term, a second term and so on... of a sequence (we do not have a "zero'th term"!
Answer:
<span>C. an=2(-4)^n-1; all integers where n>0</span>
-8/2=-4,
then the sequence is 2, -8, 32, -128, -512, 2048, ...
let
.
.
.
so clearly
and, clearly n are integers >0, since we have a 1st term, a second term and so on... of a sequence (we do not have a "zero'th term"!
Answer:
<span>C. an=2(-4)^n-1; all integers where n>0</span>
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Step-by-step explanation:
See attached picture.
First, compare the highest term of the dividend (x²) to the highest term of the divisor (x). We need to multiply the divisor by x.
When we do that, we get x² + 5x. Subtracting this from the dividend, we get -9x + 11.
Now repeat the process. Compare the highest term of the new dividend (-9x) to the highest term of the divisor (x). We need to multiply by -9.
When we do that, we get -9x − 45. When we subtract from the new dividend, we get 56.
So the quotient is x − 9, and the remainder is 56.
