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kati45 [8]
3 years ago
6

A cone has a height of 5 inches and a radius of 4 inches. What is its volume?

Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0

9514 1400 393

Answer:

  83.73 in³

Step-by-step explanation:

It is appropriate to use the formula for the volume of a cone:

  V = (1/3)πr²h

  V = (1/3)(3.14)(4 in)²(5 in) ≈ 83.73 in³

The volume of the cone is about 83.73 in³.

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I can't seem to answer this question may you guys help me
lina2011 [118]
Options A, B and E are the correct options.

Expenses are represented with negatives and income by positive.
For option E, 6x - 2.5x = 3.5x
3 0
3 years ago
What is a factor of 21x² + 13x - 20
Tems11 [23]

Answer:

(7x-5)(3x+4)

Step-by-step explanation:

4 0
3 years ago
Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distribut
defon

Answer:

0.8665 = 86.65% probability that the sample mean would be at least $39000

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125:

This means that n = 125, s = \frac{7320}{\sqrt{125}} = 654.72

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{654.72}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

0.8665 = 86.65% probability that the sample mean would be at least $39000

4 0
3 years ago
3 over 4 + 1 over 8
Dmitry [639]

Answer:

7/8

Step-by-step explanation:

Start by finding a common denominator. In this case you can turn the 4 into an 8 by multiplying by 2 but you have to do the same to the 3

2(3/4)= 6/8

Step 2: Add 6/8 + 1/8

6/8+1/8= 7/8

3 0
3 years ago
Consider a circle whose equation is x2 + y2 + 4x - 6y - 36 = 0. Which statements are true? Check all that apply.
Vlada [557]

Answer:

The answer is B and C

Step-by-step explanation:

7 0
3 years ago
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