Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
g(x)=3
Step-by-step explanation:
Let's find the answer.
W(f,g)=3e^x which can be written as:
W(f,g)=(3)*(e^x), notice that:
(e^x)=f(x) so:
W(f,g)=3*f(x), establishing:
W(f,g)=g(x)*f(x) then:
g(x)=3
In conclusion, g(x)=3.
Here, exterior angles are 1, 2, 7 & 8 as they are outside the parallel lines, & among them, alternates are: 1 with 7 and 2 & 8. 1 & 7 is not in option but 2 and 8 is there in C
In short, Your Answer would be Option C
Hope this helps!
Answer:
300
Step-by-step explanation:
60,000 / 200 = 300
Answer:
p=4
Step-by-step explanation:
because 5 is less than or equal to four!
another number grater than five no less than
so the answer is p=4
