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uranmaximum [27]
3 years ago
14

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-ax

is at (0, 3). What is the value of a for the exponential function in the graph represented in the form of f(x) = a(bx)? −4 −3 3 4
Mathematics
2 answers:
KIM [24]3 years ago
6 0

Answer:

3

Step-by-step explanation:

f(x)=a*b^x - is a formula of exponential function

As we know the point (x=0; y=3) lies at the function's  graph.

So we have to put in formula f(x)=a*b^x   x=0  f(x)=y=3

3=a*b^0   (b^0=1) => 3=a*1 => 3=a  

Alexeev081 [22]3 years ago
3 0

Answer:

The answer is C

Step-by-step explanation:

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Colby made $66.50 for mowing 7 lawns. Let x represent the number of lawns mowed and y represent the amount of money earned. Writ
Amanda [17]

Answer:

x = 9.5y

Step-by-step explanation:

7 lawns = $66.50

1 lawn = $66.50 ÷ 7

          = $9.50

You now know that for one lawn mowed, the amount of money earned is $9.50. Thus:

1x = 9.5y

x = 9.5y

6 0
2 years ago
Wane went on a 4-kilometer run he took a break at four third kilometers he took a drink of water at ten third kilometers show Wa
otez555 [7]

Answer:

Given,

The total distance covered = 4 km,

Since, initially he would be in rest,

So, his starting point would be 0.

Now, his first break = \frac{4}{3} km,

Second break = \frac{10}{3} km,

Also, we can write,

4=\frac{4\times 3}{3}=\frac{12}{3}

Drawing number line:

Step 1: Draw a line.

Step 2: Make 12 marks in same distance.

Step 3: Starts from 0, then 1/3, 2/3, 3/3 and so on.

Thus, we can show Wayne's bike on a number line as below.

6 0
3 years ago
I have a question for special product patterns.<br><br> It is in the attached image.
anastassius [24]
Its answer 3 because they are the only difference with two squared numbers
7 0
2 years ago
What would the answer to the equation 3+6x=11-4y be
klemol [59]
         6x + 3 = -4y + 11
               - 3            - 3
               6x = -4y + 8
       6x + 4y = -4y + 4y + 8
       6x + 4y = 8
6x - 6x + 4y = -6x + 8
               4y = -6x + 8
                4           4
                 y = -1¹/₂x + 2
6 0
3 years ago
Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL
scoray [572]

Answer:

8(x^2+y^2)-4x-30y+23=0

Step-by-step explanation:

<u />

<u>Distance formula</u>

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let P(x, y) = any point on the locus

Let A = (0, 2)    

Let B = (-2, 3)

If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

PA=\dfrac{1}{3}PB

Therefore, using the distance formula:

\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}

Square both sides:

\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]

\implies x^2+y^2-4y+4=\dfrac{1}{9}(x^2+4x+4+y^2-6y+9)

Multiply both sides by 9:

\implies 9x^2+9y^2-36y+36=x^2+4x+4+y^2-6y+9

\implies 8x^2+8y^2-4x-30y+23=0

\implies 8(x^2+y^2)-4x-30y+23=0

3 0
2 years ago
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