Answer:
The next resonance will be 150 Hz.
Explanation:
The frequency of the sound produced by a tube, both open and closed, is directly proportional to the speed of propagation. Hence, to produce the different harmonics of a tube, the wave propagation speed must be increased.
The frequency of the sound produced by a tube, both open and closed, is inversely proportional to the length of the tube. The greater the length of the tube, the frequency is lower.
Frecuency of the standing sound wave modes in a open-closed tube is:
fₙ=n*f₁ where m is an integer and f₁ is the first frecuency (30 Hz)
The next resonance is at 90 Hz. This means that it occurs when n = 3:
f₃=3*30 Hz= 90 Hz
This means that the next resonance occurs when n = 5:
f₅=5*30 Hz= 150 Hz
<u><em>The next resonance will be 150 Hz.</em></u>
<u><em></em></u>
#1
As we know that
now plug in all data into this
now from the formula of strain
#2
As we know that
pressure * area = Force
here we know that
now force is given as
#3
As we know that density of water will vary with the height as given below
here we know that
now density is given as
#4
as we know that pressure changes with depth as per following equation
here we know that
now we will have
here we will have
so it is 20.1 m below the surface
#5
Here net buoyancy force due to water and oil will balance the weight of the block
so here we will have
so it is 3.48 cm below the interface
Answer:
a)
Explanation:
Given paraeters are:
R = 25 cm
d = 4.7 mm
f = 60 Hz
= 160 V
a)
Where Hz and V
For
Since
From Ampere's Law:
where
So at ,
For maximum B, cos(2πft) = 1. Hence,
T
b) From r = 0 to r = R = 0.025 m, by Ampere's Law, the equation will be:
From r = R = 0.025 m to r = 0.1 m, by Ampere's Law, the equation will be:
The plot is given in the attachment.