The average velocity of the beetle is equal to the ratio between the displacement and the time:
The displacement of the beetle is
The time is t=12.8 s
Therefore, the average velocity is
in the positive x-direction.
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Answer:
–2.5 m/s²
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 25 m/s
Final velocity (v) = 0 m/s
Time (t) = 10 s
Acceleration (a) =?
Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it can be expressed as:
a = (v – u) /t
Where:
a => is the acceleration
v => is the final velocity
u => is the initial velocity
t => is the time.
With the above formula, we can obtain the acceleration of the car as follow:
Initial velocity (u) = 25 m/s
Final velocity (v) = 0 m/s
Time (t) = 10 s
Acceleration (a) =?
a = (v – u) /t
a = (0 – 25) /10
a = –25 / 10
a = –2.5 m/s²
The acceleration of the car is –2.5 m/s². The negative sign indicate that the car is decelerating i.e coming to rest.
Answer:
Explanation:
Given
acceleration of system a =1.2 m/s^2
Normal Force N=4.45 N
Force exerted F=20 N
Thus
-------1
Normal reaction 
therefore 
