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Cerrena [4.2K]
3 years ago
14

Future space stations could create an artificial gravity by rotating. Consider a cylindrical space station that rotates with a p

eriod of 28 seconds about its axis. Astronauts walk on the inside surface of the space station, and they experience an Earth-like gravitational acceleration of 9.8 m/s2. What is the diameter of the space station?
510m
145m
660m
390m​
Physics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

P = 2 pi R / v    period of space station

F / m = v^2 / R    centripetal force per unit of mass

So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2

Also, F / m = 9.8 m/s^2   earth's gravitational attraction

So 9.8 = 4 pi^2 R / P^2    or    R = 9.8 P^2 / 4 * pi^2) = 195 m

Or D = 2 R = 390 m the diameter required

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If the gravitational force between objects of equal mass is 2.30 x 10^‐8 N when the objects are 10.0 m apart, what is the mass o
Readme [11.4K]

Answer:

Mass of each objects, m = 185.69 kg

Explanation:

The gravitational force between two equal masses is, F=2.3\times 10^{-8}\ N

Separation between the masses, d = 10 m

Let m is the mass of each object. The gravitational force is given by :

F=G\dfrac{m^2}{d^2}

m=\sqrt{\dfrac{F.d^2}{G}}

m=\sqrt{\dfrac{2.3\times 10^{-8}\times (10)^2}{6.67\times 10^{-11}}}

m = 185.69 kg

So, the mass of each objects is 185.69 kg. Hence, this is the required solution.

6 0
3 years ago
Ruff, the 50 cm tall Labrador Retriever stands 3 m from a plane mirror and looks at his image. What is Ruff’s image position and
sertanlavr [38]
Since the mirror is plane, the image will be formed behind the mirror. The distance will be the same as that of the distance of the object from the mirror and the height will just be the same.
So, Ruff's image will be 3 m behind the mirror and 50 cm tall.
8 0
3 years ago
E4.Suppose Galileo’s pulse rate was 75 beats per minute. How many beats per second is this? What is the time in seconds between
Umnica [9.8K]

Answer

given,

Galileo's pulse rate = 75 beats per minutes

Beats per second

1 minutes = 60 s

pulse rate = \dfrac{75}{60}

                  = 1.25 beats/s

times in second

t = \dfrac{1}{1.25}

      t = 0.8 s/pulse

distance of the object

initial velocity = 0 m/s

s = ut + \dfrac{1}{2}gt^2

s = \dfrac{1}{2}\times 9.8\times 0.8^2

      s = 3.14 m

distance in feet

  1 m = 3.28 ft

 3.14 m = 3.14 x 3.28 ft

             = 10.3 ft

distance in feet is equal to 10.3 ft.

3 0
4 years ago
Which of the following is true for balancing equations? A. There must be an equal number of atoms of each element on both sides
Zielflug [23.3K]
<h3><u>Answer</u>;</h3>

A. There must be an equal number of atoms of each element on both sides of the equation.

<h3><u>Explanation;</u></h3>
  • Chemical equations need to be balanced in order to satisfy the law of conservation of matter, which states that in a closed system matter is neither created nor destroyed.
  • The number of atoms of each element should be equal on either side of the equation, that is the reactants and product side.
3 0
3 years ago
cylindrical container is to be constructed to be open at the top with a volume of 27π cubic meters using the least amount of mat
Llana [10]

Answer:

radius comes out to be 3 m

height of the cylinder comes out to be 3m

Explanation:

given

volume of cylinder = 27π m³

π r² h = 27π

   r² h = 27.............(1)

surface area of cylinder open at the top

S = 2πrh + π r²

S = 2\pi \dfrac{27}{r} + \pi r^2

\frac{\mathrm{d} s}{\mathrm{d} r}=\frac{\mathrm{d}}{\mathrm{d} r} (2\pi \dfrac{27}{r} + \pi r^2)

\frac{\mathrm{d} s}{\mathrm{d} r}=54\pi \dfrac{-1}{r^2}+2\pi r

\frac{\mathrm{d} s}{\mathrm{d} r}=0

for least amount of material requirement.

\dfrac{54\pi }{r^2} = 2\pi r\\r=3m

hence radius comes out to be 3 m

for height put the value in the equation 1

so, height of the cylinder comes out to be 3m

3 0
3 years ago
Read 2 more answers
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