<u><em>Answer:</em></u>x = 7
MN (first base) = 17 units
OP (second base) = 21 units
QR (median) = 19 units
<u><em>Explanation:</em></u>In a trapezium, the length of the median is equal to half the sum of the two bases.
<u>From the given, we have:</u>
MN (first base) = 17 units
OP (second base) = 5x - 14 units
QR (median) = x + 12 units
<u>Applying the above rule:</u>
median = 0.5 (first base + second base)
x + 12 = 0.5 (17+5x-14)
2(x+12) = 17+5x-14
2x + 24 = 3 + 5x
24-3 = 5x-2x
21 = 3x
x =

x = 7
<u>Based on the above, the lengths would be:</u>
MN (first base) = 17 units
OP (second base) = 5x - 14 = 5(7) - 14 = 21 units
QR (median) = x + 12 = 7 + 12 = 19 units
Hope this helps :)
Answer:
(x, y) = (-10, 5)
Step-by-step explanation:
This one can be a little tricky because the variables in the equations are not in the same order. It might help to rewrite the system as ...
Multiplying the first equation by 3 and subtracting 2 times the second equation can eliminate the y-variable:
3(5x +6y) -2(2x +9y) = 3(-20) -2(25)
11x = -110 . . . . . . simplify
x = -10 . . . . . . . . divide by 11
5(-10) +6y = -20 . . . substitute for x in the first equation
6y = 30 . . . . . . . . add 50
y = 5 . . . . . . . . . . divide by 6
The solution is (x, y) = (-10, 5).
Answer:
1). x° + 100° + 120° + 100° = 360°
2). x = 40
Step-by-step explanation:
Formula for the sum of the interior angles of a polygon = 
Where n = number of sides of the polygon
From the picture attached,
For n = 4,
Sum of the interior angles of the given polygon = (4 - 2) × 180°
= 360°
Therefore, equation for the sum of interior angles will be,
x° + 100° + 120° + 100° = 360°
x° + 320° = 360°
x° = 360° - 320°
x° = 40°
You have the following expression:

By definition, when you want to express a fraction as a decimal number, you must divide the numerator by the denominator. Knowing this, you get the following:

You can identify that:

Based on the above, you can determine that the best estimate for the sum is:

The answer is option d:
Answer:
answer 3
Step-by-step explanation: