Describe how the graph of y= x^2 can be transformed to the graph of the given equation.
2 answers:
Answer:
We conclude that the graph y = x² can be transformed into the graph of the given equation y = (x - 12)²+3 by shifting the graph of y = x² right 12 units and then up 3 units.
Hence, option D is true.
Please check the attached graph.
Step-by-step explanation:
Given the parent function
y = x²
Given the transformed function
y = (x - 12)²
Horizontal Translation:
The horizontal translation of y = x² is of the form
f(x-h)
so y = y = (x - 12)² means y = x² is shifted 12 right.
Vertical Translation:
y = x²
Then y = x² + b is a vertical translation of y = x²
if b > 0, then y = x² + b is the graph of y = x² 'b' units up.
if b < 0, then y = x² + b is the graph of y = x² 'b' units down.
Thus, y = x² + 3 means the graph y = x² is vertically shifted up by 2 units.
Please check the attached graph.
- The blue graph is representing the graph of y = x².
- The red graph is representing the graph of y = (x - 12)²+3
Therefore, the graph y = x² can be transformed into the graph of the given equation y = (x - 12)²+3 by shifting the graph of y = x² right 12 units and then up 3 units.
Hence, option D is true.
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Answers:
Lower bound = 41.3
Upper bound = 41.5
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Explanation:
49.15 is the smallest f can be while 49.24 is the largest it can be. Well technically we could have something like 49.2499 or 49.24999 and so on. We slowly approach 49.25 but never actually get there
So the variable f is between 49.15 and 49.25 inclusive of the first value but excluding the second value. We can write it as
For similar reasoning,
-----------------
If we wanted to subtract those variables and get the smallest result possible, then we need to pick values that are closest together. It might help to set up a number line.
This means we'd go for f = 49.15 and g = 7.85
The lower bound for f-g is f-g = 49.15-7.85 = 41.3
In contrast, the upper bound is when the two variables are spaced as far apart as possible. The upper bound is f-g = 49.25 - 7.75 = 41.5
Answer:
After 80 years 432 pounds of radioactive element will be remaining.
Step-by-step explanation:
A function models the amount of a radioactive material.
Here x = number of years taken for decay.
If pound and
pound, then we have to calculate the time for decay.
Take log on both the sides of the equation
-0.0077x = ln(0.54)
-0.0077x = -0.616186
x =
x = 80.02 years
Therefore, After 80 years 432 pounds of radioactive element will be remaining.