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ehidna [41]
3 years ago
12

What is the missing reason in the proof

Mathematics
2 answers:
amid [387]3 years ago
7 0

Answer:

Option C. Transitive property of equality

Step-by-step explanation:

It is given in the question AB ≅ CD and CF ≅ EB

and we have to prove that AE ≅ FD

Since AB = AE + EB

and CD = CF + FD

AB ≅ CD [Given]

So, AE + EB ≅ CF + FD

Since CF ≅ EB  [Given]

So, AE ≅ FD [Transitive property]

Hence Option C. Transitive property of equality will be the answer.

Vesna [10]3 years ago
5 0
I believe (C), is your answer....Transitive Property of Equality



Hope that helps!!!
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What is the perimeter of a rectangle with a length of 6cm and a width of<br> 5cm?
Nataliya [291]

Answer:

perimeter = 22 cm

Step-by-step explanation:

perimeter = 2(L + W) = 2(6 + 5) = 22 cm

8 0
3 years ago
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A die is rolled once what is the probability of rolling not a 4
snow_lady [41]

Answer:

I think 1/6

Step-by-step explanation:

A die has 6 sides so every side has 1/6 chance to land on

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3 years ago
A test for marijuana usage was tried on 170 subjects who did not use marijuana. The test result was wrong 8 times.a. Based on th
motikmotik

Answer:

a. 0.047

b. Unlikely.

Step-by-step explanation:

a. The probability of a test result being wrong for a person not using mrijuana  = 8 / 170 = 0.047.

b. As the probability for a wrong result is < 0.05 we can say that the test is unlikely to be wrong.

6 0
3 years ago
What percent of 150 is 162
Novay_Z [31]
To find a percentage of a number, you divide by that number.
So to find what percent of 150 162 is, you divide 162 by 150
162 ÷ 150 = 1.08
Now, to find the percentage, we take the decimal and move the point two places to the right.
1.08 = 108%
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5 0
3 years ago
We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
3 years ago
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