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3 years ago

Solve. 2x/21= 32/42 a. 8 b. 27.1 c. 32 d. 16

Mathematics

2 answers:

hichkok12 [17]3 years ago

5 0

I think the answer would be 8 but I may be wrong

inna [77]3 years ago

4 0

Answer:

a. 8

Step-by-step explanation:

hope this helps

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Step-by-step explanation:

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Testing for a disease can be made more efficient by combining samples. If the samples from four people are combined and the mixt

Ilya [14]

Answer:

There is a 34.39% probability of a positive result for four samples combined into one mixture.

This probability is not low enough so that further testing of the individual samples is rarely necessary,

Step-by-step explanation:

There are only two possible outcomes. Either a sample tests positive, or it does not, so we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses x is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

There are four samples, so $n = 4$

Each sample has a probability of 0.1 of being positive, so $\pi = 0.1$ .

Assuming the probability of a single sample testing positive is 0.1, find the probability of a positive result for four samples combined into one mixture.

If any sample is positive, the result of the four samples is positive. So this is $P(X>0)$ . Either the number of positive samples is 0, or it is greater than 0. The sum of the probabilities is decimal 1. So: