Answer:
(i)= 45 KPH, (ii) = 251 miles
Step-by-step explanation:
'Per' essentially means divide. Thus, to find Kilometres per hour, divide 270 by 6= 45. The bus is travelling at 45 KPH.
Then, to see how far a nine hour trip would cover, distance = speed * time = 251 miles.
Answer:
4^5x-1=16
4^5x-1=4²eliminate 4
5x-1=2
5x=2+1
5x=3
x=3/5
log4(10x+2)=1
log4(10x+2)=log4 ⁴
eliminate log4
10x+2=4
10x=4-2
10x=2
x=2/10
x=1/5
difference between the is we use law of indices and logarithm to the questions respectively
similarities is we eliminate there base
Answer:
Therefore the work done is 640 ft pound.
Step-by-step explanation:
Given that, a heavy rope 40 ft long, weighs 0.8 lb/ft.
Force = weight.
Let we pull x ft. Then the remain rope = (40-x)ft.
(40-x) ft it is variable.
The weight of (40-x) ft is =(40-x)0.8 lb
∴ Force =(40-x)0.8 lb
Work done = Force × displacement
= (40-x)0.8 Δx [ displacement = Δx]
Therefore ΔW =(40-x)0.8 Δx
Since total rope is pulling up on the top of the building. Total displacement = 40 ft.
Total work done 
![=[32x-\frac{0.8x^2}{2}]_0^{40}](https://tex.z-dn.net/?f=%3D%5B32x-%5Cfrac%7B0.8x%5E2%7D%7B2%7D%5D_0%5E%7B40%7D)
![=[(32\times 40)-0.4(40)^2]](https://tex.z-dn.net/?f=%3D%5B%2832%5Ctimes%2040%29-0.4%2840%29%5E2%5D)
=640 ft pound.
Therefore the work done is 640 ft pound.
Answer:

So the discount is 33% and we are paying 67% of the value. The reason is given by the relative change:

Step-by-step explanation:
First we have a first discount of 40% so then using this condition and assuming that
represent the initial price, the price after the first discount
is given by:

That means 60% of the original value.
Now we have another discount of 45% for the 60% reamining after a 2 discount so let's
represent the price after the second disccount we can can express this price in terms of
or
liek this:


So the discount is 33% and we are paying 67% of the value. The reason is given by the relative change:
