A taxable item cost $48. The sales tax rate is 8%. What will be the amount of tax on the item

There is 3/4 pound of cream in a containwr. Julian will use 3/8 pound of cream to make crème brûlée. What fraction of a pound of

Ksivusya [100]

Answer:

$\frac{3}{8}\ pound$ of cream will remain in the container.

Step-by-step explanation:

Given:

Amount of cream in the container = $\frac{3}{4}\ pound$

Amount of cream used to make crème brûlée = $\frac{3}{8}\ pound$

We need to find the amount of cream remain in the container.

Solution:

Now we can say that;

the amount of cream remain in the container is equal to Amount of cream in the container minus Amount of cream used to make crème brûlée.

framing in equation form we get;

amount of cream remain in the container = $\frac{3}{4}-\frac{3}{8}$

Now we will make the denominator common using LCM we get;

amount of cream remain in the container = $\frac{3\times2}{4\times2}-\frac{3\times1}{8\times1}= \frac{6}{8}-\frac{3}{8}$

Now denominators are common so we will solve the numerators.

amount of cream remain in the container = $\frac{6-3}{8}=\frac{3}{8}\ pound$

Hence $\frac{3}{8}\ pound$ of cream will remain in the container.

7 0

3 years ago

Solve for y in terms of x.

krek1111 [17]

<u>Answer:</u>

$y=\frac{3}{2} x+6$

<u>Step-by-step explanation:</u>

We are given the following equation and we are supposed to solve y in terms of x. It simpler terms, it means that we have to make y the subject of the equation while x being used in it as it is:

$\frac{2}{3} y-4=x$

Taking the constant 4 to the side where x is to get:

$\frac{2}{3} y=x+4$

Multiplying the denominator 3 to the other side of the equation to get:

$2y=3x+12$

Isolating y to make it the subject:

$y=\frac{3}{2} x+\frac{12}{2}\\ \\y=\frac{3}{2} x+6$

3 0

2 years ago

Write the domain AND range of the following graph.

Effectus [21]

Answer:

Domain: (-∞,∞), Range: [2,∞)

3 0

2 years ago

Find the slope of the line through the given points (1,6),(-8,-9)

cestrela7 [59]

The answer to the question

6 0

2 years ago

Larry has a gift card worth 400 for a local entertainment store Movies cost $20 each and newly released video games cost $50 eac

Vikki [24]

Answer:

All are correct.

Step-by-step explanation:

Let x be the number of movies and y be the number of newly released video games.

Larry has a gift card worth 400 for a local entertainment store Movies cost $20 each and newly released video games cost $50 each.

$20x+50y\leq 400$

Larry must purchase at least nine items.

$x+y\geq 9$

Check both inequalities of all given ordered pairs.

For (5,6),

$20(5)+50(6)\leq 400\Rightarrow 400\leq 400$

$5+6\geq 9\Rightarrow 16\geq 9$

Point (5,6) satisfy both inequalities.

For (10,4),

$20(10)+50(4)\leq 400\Rightarrow 400\leq 400$

$10+4\geq 9\Rightarrow 14\geq 9$

Point (10,4) satisfy both inequalities.

For (20,0),

$20(20)+50(0)\leq 400\Rightarrow 400\leq 400$

$20+0\geq 9\Rightarrow 20\geq 9$

Point (20,0) satisfy both inequalities.

For (15,2),

$20(15)+50(2)\leq 400\Rightarrow 400\leq 400$

$15+2\geq 9\Rightarrow 17\geq 9$

Point (15,2) satisfy both inequalities.

Therefore, all combination of movies and newly released video games Larry could purchase using his gift card.

4 0

3 years ago