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postnew [5]
3 years ago
15

What is the atomic mass of 3NaCl

Chemistry
1 answer:
givi [52]3 years ago
8 0

Answer:

35.453

Explanation:

You might be interested in
Select all that apply to physical and chemical properties ?
MaRussiya [10]

Answer:

•   Chemical properties can only be observed during a chemical reaction:

Chemical properties can only be established by changing a substance's chemical identity, and chemical properties are different from physical properties, which can be observed by viewing or touching a sample. The internal qualities of a substance must be altered to determine its chemical properties.

Examples:

Some common chemical properties are heat of combustion, enthalpy of formation, toxicity,

and flammability, each of which will be covered in this lesson.

•   Rusting of iron is the chemical reaction not physical because:

The rusting of iron is a chemical change because it is two substances reacting together to make a

new substance. When iron rusts, iron molecules react with oxygen molecules to make a compound

called iron oxide. Rusting would only be a physical change if iron molecules remained pure iron

throughout the process.

The equation for this reaction is: 4Fe+ 3O2 → 2Fe2O

•   Melting and boiling points are physical properties:

Yes melting and boiling points are the physical properties.  

Physical properties can be observed or measured without changing the composition of matter. Physical properties are used to observe and describe matter.  

Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others.

•   Mass and volume are chemical properties:

No mass and volume are the extensive physical properties of matter

All properties of matter are either physical or chemical properties and physical properties are either intensive or extensive.

Extensive properties, such as mass and volume, depend on the amount of matter being measured.

Intensive properties, such as density and color, do not depend on the amount of the substance present.

Physical properties can be measured without changing a substance’s chemical identity.

•   Various components of a mixture do not combine chemically:

When various components of a mixture do not combine chemically it is a Combination of substances in which individual components do not combine chemically but retain their individual properties. Mixture in which one or more substances are distributed evenly in another substance.

When various components combine chemically then form chemical compounds that are often divided into two categories. Metals often react with nonmetals to form ionic compounds. These compounds are composed of positive and negative ions formed by adding or subtracting electrons from neutral atoms and molecules


7 0
3 years ago
Read 2 more answers
Which of the following shows the 3 main jobs of a cell?
skad [1K]
C is the answer hope this helps
8 0
3 years ago
determine the frequency and wavelength (in nm) of the light emitted when the e- fell from n=4 and n=2
Lostsunrise [7]

Answer:

Frequency = 6.16 ×10¹⁴ Hz

λ = 4.87×10² nm

Explanation:

In case of hydrogen atom energy associated with nth state is,

En =  -13.6/n²

For n = 2

E₂ = -13.6 / 2²

E₂ = -13.6/4

E₂ = -3.4 ev

Kinetic energy of electron = -E₂ = 3.4 ev

For n = 4

E₄ = -13.6 / 4²

E₄ = -13.6/16

E₄ = -0.85 ev

Kinetic energy of electron = -E₄ = 0.85 ev

Wavelength of radiation emitted:

E = hc/λ = E₄ - E₂

hc/λ = E₄ - E₂

by putting values,

6.63×10⁻³⁴Js × 3×10⁸m/s / λ = -0.85ev   - (-3.4ev )

6.63×10⁻³⁴ Js× 3×10⁸m/s / λ = 2.55 ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s  /2.55ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s  /2.55× 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 2.55× 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 4.08×10⁻¹⁹ J

λ = 4.87×10⁻⁷ m

m to nm:

4.87×10⁻⁷ m ×10⁹nm/1 m

4.87×10² nm

Frequency:

Frequency = speed of electron / wavelength

by putting values,

Frequency = 3×10⁸m/s /4.87×10⁻⁷ m

Frequency = 6.16 ×10¹⁴ s⁻¹

s⁻¹ = Hz

Frequency = 6.16 ×10¹⁴ Hz

3 0
3 years ago
Give 4 Economics activities associated with water​
MAXImum [283]

Answer:

For large rivers the problem is not simply a matter of deduction of consumptive use from runoff: it is more complex and the complexity is related to the changes in .

Explanation:

6 0
3 years ago
Helium occupies a volume of 3.8 L at –45°C. What was its initial temperature when it occupied 8.3 L?
USPshnik [31]

Answer:

98.3 gradius Celsius

Explanation:

This problem is solved using the Ideal Gas Equation

pV = nRT

...

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

3 0
3 years ago
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