Consider the equation for calculating molarity: (no. of mole of solute)÷(volume of solution)
First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass
no. of mole of 85.0g of AgNO3 = 85.0/(107.9+14.0+16.0x3)
=0.5mol
Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.
Volume of solution = 500/1000
= 0.5 dm3
Therefore, the molarity is
0.5/0.5
=1.0M
The answer should be B.
Hello the answer is C i hope this helps you
A. The longest carbon chain is eight, and it has two methyl groups attached to carbon three, and a special group attached to carbon five. Its two names could be:
3-dimethyl-5-(1-methylethyl)octane
3-dimethyl-5-isopropyloctane
Both of these are correct. This is an alkane, because it has all single bonds.
B. This has a triple bond contained between carbons 2 and 3, and has a methyl group off carbon 4. The longest chain is 5. It’s name is:
4-methyl-2-pentyne
This is an alkene, because of the double bond.
C. This has a double bond contained between carbons 2 and 3, and has a methyl off of four and an methyl off of six. The longest chain is eight (follow the longest chain of carbons).
4,6-dimethyl-2-octene
This is an alkene, because of the double bond.
D. This has an ethyl group at 1 and a methyl group at 2 (rotate the compound to make it as clean as possible, in this case, the ring is flipped and rotated to make it alphabetical with the smallest numbers possible). The two names are:
1-ethyl-2-methylbenzene
ortho-ethylmethylbenzene
Both are correct, the ortho prefix telling the location of the ethyl and methyl groups. This is an aromatic structure because of its double bonded ring.
E. The longest chain is nine, and has methyls at three, five, and seven, along with a propyl at five. The name is:
3,5,7-trimethyl-5-propylnonane
This is an alkane, due to the single bonds.
Hope this helps!
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