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3 years ago

What happens when the threat of exposure to dirty air is reduced in a community?

Chemistry

2 answers:

viktelen [127]3 years ago

6 0

There is enough oxygen available for people's lungs to function normally

Explanation:

When the threat of exposure to dirty air is reduced in a community is reduced there will be enough oxygen available for people's lungs to function normally.

The main problem with dirty air is the absence or lack of oxygen in the atmosphere for people to breathe in calmly and easily.

Air pollution is the introduction of harmful substance into the atmosphere.
These pollutants makes breathing very difficult because other gases are concentrated in the air.
when air is purified through the halt in the processes that feeds the pollutants in, there is enough available oxygen to breathe in.

learn more:

Point source pollution brainly.com/question/11271230

#learnwithBrainly

ss7ja [257]3 years ago

6 0

Answer:

Explanation:

I just took the test.

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Balance each of the following in BASE: Show work

kupik [55]

Answer : The balanced chemical equation in a basic solution are,

(A) $2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr(OH)_3+4OH^-+3Cu(OH)_2$

(B) $2NO_2+2OH^-\rightarrow NO_3^-+H_2O+NO_2^-$

(C) $4Zn+7OH^-+NO_3^-+6H_2O\rightarrow 4[Zn(OH)_4]^{2-}+NH_3$

(D) $Br_2+12OH^-+5Br_2\rightarrow 2BrO_3^-+6H_2O+10Br^-$

Explanation :

(A) The given chemical reaction is :

$CrO_4^{2-}(aq)+Cu(s)\rightarrow Cr(OH)_3(s)+Cu(OH)_2(s)$

The oxidation-reduction half reaction will be :

Oxidation : $Cu\rightarrow Cu^{2+}+2e^-$

Reduction : $CrO_4^{2-}+4H_2O+3e^-\rightarrow Cr^{3+}+8OH^-$

In order to balance the electrons, we multiply the oxidation reaction by 3 and reduction reaction by 2 then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr^{3+}+16OH^-+3Cu^{2+}$

or,

$2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr(OH)_3+4OH^-+3Cu(OH)_2$

(B) The given chemical reaction is :

$NO_2(g)\rightarrow NO_3^-(aq)+NO_2^-(aq)$

The oxidation-reduction half reaction will be :

Oxidation : $NO_2+2OH^-\rightarrow NO_3^-+H_2O+1e^-$

Reduction : $NO_2+1e^-\rightarrow NO_2^-$

The electrons in both the reactions are balanced. Now added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$2NO_2+2OH^-\rightarrow NO_3^-+H_2O+NO_2^-$

(C) The given chemical reaction is :

$Zn(s)+NO_3^-(aq)\rightarrow Zn(OH)_4^{2-}(aq)+NH_3(g)$

The oxidation-reduction half reaction will be :

Oxidation : $Zn+4OH^-\rightarrow [Zn(OH)_4]^{2-}+2e^-$

Reduction : $NO_3^-+6H_2O+8e^-\rightarrow NH_3+9OH^-$

In order to balance the electrons, we multiply the oxidation reaction by 4 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$4Zn+7OH^-+NO_3^-+6H_2O\rightarrow 4[Zn(OH)_4]^{2-}+NH_3$

(D) The given chemical reaction is :

$Br_2(l)\rightarrow BrO_3^-(aq)+Br^-(aq)$

The oxidation-reduction half reaction will be :

Oxidation : $Br_2+12OH^-\rightarrow 2BrO_3^-+6H_2O+10e^-$

Reduction : $Br_2+2e^-\rightarrow 2Br^-$

In order to balance the electrons, we multiply the reduction reaction by 5 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$Br_2+12OH^-+5Br_2\rightarrow 2BrO_3^-+6H_2O+10Br^-$

7 0

3 years ago

The physical state in which a substance has a no definite volume is:

AlekseyPX

The physical state in which a substance has no definite volume is gas.

7 0

3 years ago

A 5.5 × 10–3 M solution of fluoroacetic acid, CH2FCOOH, has a pH of 2.57. What is the acid-dissociation constant, K a, of this a

lianna [129]

The acid dissociation constant is 1.3 × 10^-3.

<h3>What is acid-dissociation constant?</h3>

The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;

Let the acid be HA;

HA + H2O ⇄ H3O^+ + A^-

since the pH of the solution is 2.57 then;

[H3O^+] = Antilog(-pH) = Antilog(-2.57) = 2.7 × 10^-3

We can see that; [H3O^+] = [A^-] so;

Ka = (2.7 × 10^-3)^2/(5.5 × 10^–3)

Ka = 1.3 × 10^-3

Learn more about acid-dissociation constant: brainly.com/question/9728159

6 0

2 years ago

Which of the following statements does not describe the structure of an atom?

hammer [34]

Answer:

the last one is wrong

Explanation:

wrong : most of the mass of an atom comes from the electrons cloud

3 0

3 years ago

Why is earth's surface warmer in the northern hemisphere when it is summer there

RideAnS [48]

By definition, summer is the portion of the year in which the hemisphere is tilted toward the sun, so that sunlight strikes the surface more directly. When it is summer in the northern hemisphere, it is winter in the southern hemisphere, and vice versa

5 0

3 years ago

Read 2 more answers