Question

What is the mole fraction of NaCl in

Answer 1

Answer:0.192 for acellus

Explanation:

Answer 2

The mole fraction of NaCl in  a mixture : 0.195

Further explanation

The mole fraction shows the mole ratio of the compound to the moles of the mixture/solution

Can be formulated :

$\tt x_1=\dfrac{n_1}{n_{tot}}$

n tot = n₁+n₂+....nₙ

a mixture of 0.564 g NaCl, 1.52 g KCI, and 0.857 g LiCl

• mol NaCl (MW=58.44 g/mol)

$\tt \dfrac{0.564}{58,44 g/mol}=0.0097$

• mol KCl(MW=74.55 g/mol)

$\tt \dfrac{1.52}{74.55}=0.02$

mol LiCl(MW=42,394 g/mol)

$\tt \dfrac{0.857}{42,394 g/mol}=0.02$

n total =

$\tt 0.0097+0.02+0.02=0.0497$

the mole fraction of NaCl :

$\tt \dfrac{0.0097}{0.0497}=0.195$