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alexandr1967 [171]
3 years ago
14

Find the difference 5 2/3 - 3 1/5 A. 5 2/3 B. 8 13/15 C. 2 7/15 D. 3 1/5

Mathematics
1 answer:
RSB [31]3 years ago
3 0

To find the difference of given expression:

5\frac{2}{3} -3\frac{1}{5}

First step is to subtract the whole number5 and 3.

So, 5 - 3 = 2.

Now we can find the difference of fractions.

To subtract the fractions , we need to find the common denominator.

Common denominator of 3 and 5 is 15.

So, we need to make both the denominator equal to 15.

\frac{2}{3} =\frac{2*5}{3*5} =\frac{10}{15}

Similarly, \frac{1}{5} =\frac{1*3}{3*5} = \frac{3}{15}

Therefore, \frac{2}{3} -\frac{1}{5} =\frac{10}{15} -\frac{3}{15}

=\frac{10-3}{15}

= \frac{7}{15}

So, the difference of given expression is 2\frac{7}{15}.

So, the correct choice is C.

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Answers:

- DH is <u>correct</u> because a line is connecting the two points D and H as shown in the image, forming a <u>line segment</u>.

- ED is <u>correct</u> because a line is connecting the two points D and E, forming another <u>line segment</u>, as shown in the drawing.

- EH is <u>incorrect</u> because in the drawing shown, there is no line connecting the two points E and H, so there would be <u>no line segment</u> formed between these two points.

- CD is <u>correct</u> because there is another line connecting the two points C and D, forming another <u>line segment</u> in the drawing.

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8 0
3 years ago
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
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Answer:

The irrational conjugate theorem states that if a polynomial equation has a root (a + √b), then we can say that the conjugate of (a + √b), i.e. (a - √b) will also be another root of the polynomial.

Step-by-step explanation:

The irrational conjugate theorem states that if a polynomial equation has a root (a + √b), then we can say that the conjugate of (a + √b), i.e. (a - √b) will also be another root of the polynomial.

For example, if we consider a quadratic equation x² + 6x + 1 = 0, then two of its roots are - 3 + √8 and - 3 - √8 and they are conjugate of each other. (Answer)

7 0
3 years ago
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