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Dahasolnce [82]

2 years ago

7

Ms. Simpson gives her class the following problem:Simplify: 3 (x-2) + 6x. Mikey

2 answers:

kow [346]2 years ago

4 0

Answer:

me hahahaah

Step-by-step explanation:

Schach [20]2 years ago

3 0

Answer:

first off, when did Marge become a teacher

Step-by-step explanation:

Second off, he didn't flip the sign inside of the parentheses.

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Let v1=(3,5) and v2=(-4,7) Compute the unit vectors in the direction of |v1| and |v2|?

AleksandrR [38]

By definition, the unit vector of v = (a,b) is
$\hat{v} = \frac{\vec{v}}{|v|}$

Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
(3,5)/√[3² + 5²]
= (3,5)/√34

The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65

Answer:
The unit vector of v₁ in the direction of |v₁} is $( \frac{3}{\sqrt{34}} , \frac{5}{\sqrt{34}} )$
The unit vector of v₂ in the directin of |v₂| is
$( \frac{-4}{\sqrt{65}} , \frac{7}{\sqrt{65}} )$

6 0

3 years ago

Anika [276]

Answer:a,c,d

Step-by-step explanation:

8 0

2 years ago

Could anyone help me on this question?

Amanda [17]

Answer:

it A ;)

Step-by-step explanation:

7 0

3 years ago

Fynjy0 [20]

Answer:

PQ R s parallelogram

< Q = < s = 114

< P = 180 _ 114 = 66

<2 = 66 / 2 = 33

< I = 114 / 2 = 5 7

< I + < 2 = 3 3 + 57 = 90

< ( STP ) = 90

TP I ST

3 0

2 years ago

Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi

miss Akunina [59]

Answer:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

Step-by-step explanation:

1st boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a$

Equation:

$y=ax^2 -2ax+c$

The y-coordinate of the vertex:

$y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1$

Solve:

$c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}$

Parabola equation:

$y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}$

2nd boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0$

Equation:

$y=ax^2+c$

The y-coordinate of the vertex:

$y_v=a\cdot 0^2+c\Rightarrow c=-7$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-7\\ \\64a-7=1$

Solve:

$a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7$

Parabola equation:

$y=\dfrac{1}{8}x^2 -7$

System of two equations:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

7 0

3 years ago

Read 2 more answers