There are many reasons one may want to simplify, rearranging to find specific values - or maybe just making it simpler
Well, let's do some examples:
y(x(3+2)) +2 = -2y +2 <span>< I just made this one up, it looks really complicated right now, none the less it can be simplified easily
</span>y(3x+2x) + 2 = - 2y +2
3xy + 2xy + 2 = -2y +2
5xy + 2 = -2y +2 <-- the +2's dissapear because they cancel out
5xy = -2y
<span>And there we have it, that long expression has been simplified to something really simple.
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Another example:
3(4(x+3(2 +z)) - 5)= 3y <span><- you can start where ever, I like starting in the middle
</span>3 * (4 * (x + 3*(2 + z)) - 5 ) = 3y <span><- here it is spaced out, we get a much better view
</span><span>3 * (4 * (x + 6 + 3z) - 5 ) = 3y</span>
3 * (4x + 24 + 12z - 5) = 3y <- divide both sides by 3 ..
4x + 24 + 12z - 5 = y <- much better
<span>
</span>Note: Simplify means solving to a degree, but you can't solve it because it has unknowns
Answer:
70% of 0.6 kg is 0.42 kg. To find this you would multiply 0.70 by 0.6.
Nah stop cheating in Fullard class smh:
Step-by-step explanation:
1.A.
The base lengths of the trapezoid are 35cm and 19cm. The height is 15cm.
1.B.
The formula for the area of a trapezoid is
A=(b1+b2)/2*h
plug in the data we know
A=(35+19)/2*15
A=54/2*15
A=27*15
A=405cm²
since there are two trapezoids, we double that number 405*2=810cm²
Answer=810cm²
1.C.
To solve for this, we need to find the perimeter of the trapezoid
P=35+19+17+17=88cm
Answer=No. The edges of the trapezoid are longer than 80cm.
2.A.
3units. Since their x values are the same, you just subtract the y values to calculate distance 5-2=3
Answer=3
2.B
A right triangle. Since one coordinate is directly above, and the other is directly to the right of the bench
3.A
The two triangles would be...
A=1/2b*h=1/2*30*72=15*72=1080ft² each
and the center rectangle would be
A=l*w=20*72=1440ft²
Add them all together and you get
Total area=3600ft²
