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lorasvet [3.4K]
4 years ago
14

Question:

Mathematics
1 answer:
alexandr1967 [171]4 years ago
5 0

Answer:

Part 1) The draw in the attached figure

Part 2) m\angle ABD=50^o

Step-by-step explanation:

Part 1)  Draw the described circle

The draw in the attached figure

Part 2) What is the measure of angle ABD

step 1

Find the measure of arc AD

Remember that

arc\ AD+arc\ DC+arc\ AC=360^o ----> by complete circle

substitute the given values

arc\ AD+124^o+68^o=360^o

arc\ AD=360^o-192^o=168^o

step 2

Find the measure of angle ABD

we know that

The measurement of the external angle is the half-difference of the arches that comprise

In this problem

The measure of angle ABD is an external angle

so

m\angle ABD=\frac{1}{2} [arc\ AD-arc\ AC]

substitute the given values

m\angle ABD=\frac{1}{2} [168^o-68^o]=50^o

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Answer:

w = 21.4 ft

Step-by-step explanation:

Area of Trapezoid = Area = (a+b)/2 * h

Where a and b are the bases of trapezoid, and h is the height.

In the figure we are given:

a= 32.3 ft

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h= 22.9 ft

Area = 614.865 ft²

Putting values in formula

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1229.73 = 32.3 + w * 22.9

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=> w = 21.4 ft

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3 years ago
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Answer:

See the attached figure which represents the problem.

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