Given: sin theta = 2/5. This tells us that the lengths of the opp side and the hyp are 2 and 5 respectively. The adj side is found using the Pyth. Thm.: 5^2-2^2= 25-4 = 21, so that the adj side is sqrt(21).
The double angle formula for the sine is sin 2theta = 2 sin theta *cos theta.
In this particular problem, the sine of 2theta is 2*(2/5)*[sqrt(21) / 5], or:
(4/25)*sqrt(21).
Only use this one pls. Lol
Answer:
this is confusing. I'll try my best to sort it out for you. I'll tap in once I figure it out
Step-by-step explanation:
-2 (4a + 4b) + 5a > -35
-8a -8b + 5a > -35
-3a -8b > -35
for a
-3a > -35 + 8b
a < -35 + 8b ÷ -3
a < 35 - 8b ÷ 3
for b
-3a - 8b > -35
-8b > -35 + 3a
b < -35 + 3a ÷ -8
b < 35 - 3a ÷ 8
