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3 years ago

It always confuses me when they make me do the baby steps

Mathematics

1 answer:

fgiga [73]3 years ago

5 0

A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by 2.

3x-y=0 → 2(3x-y=0) = 6x - 2y = 0

5x+2y=22

The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22

B. So now we combine them:

6x - 2y = 0

+ + +

5x + 2y = 22

= = =

11x + 0 = 22 ← The answer

C. Now that we have the equation 11x = 22, we solve for x

11x = 22 ← Divide both sides by 11

x = 2 ← The answer

D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:

5(2)+2y = 22

10 + 2y = 22

2y = 12

y = 6

Therefore, the solution to this problem is x = 2 and y = 6

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What percent of 82.5 is 21.12

Travka [436]

21.12 is 25.6% of 82.5

hope this helps!! :)
have a good day!! :D
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8 0

3 years ago

Read 2 more answers

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

#learnwithBrainly

7 0

3 years ago

What is the nth term of the sequence? 4, 2, 0, –2, ..

tatuchka [14]

' n ' the 'n'th term

1    4
2    2
3    0
4 -2 .

In general, the 'n'th term of the sequence is A(n) = 6 - 2n .

3 0

3 years ago

The angles shown are complementary angles. The measure of angle 1 is (14x-21) degrees and the measure of angle 2 is (4x+75)

Anni [7]

Answer:

A complementary angle is an angle that adds up to 90 degrees. supplementary angles add up to 180 degrees. So a supplementary angle lies on a single, straight line, and a complementary angle is a right angle.

Step-by-step explanation:

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3 years ago

Q5 Q3.) How far, to the nearest foot, is the ship from the statue's base?

dusya [7]

Distance from base = 305 / tan(29.5deg)
= 539 ft

7 0

3 years ago