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3 years ago

It always confuses me when they make me do the baby steps

Mathematics

1 answer:

fgiga [73]3 years ago

5 0

A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by 2.

3x-y=0 → 2(3x-y=0) = 6x - 2y = 0

5x+2y=22

The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22

B. So now we combine them:

6x - 2y = 0

+ + +

5x + 2y = 22

= = =

11x + 0 = 22 ← The answer

C. Now that we have the equation 11x = 22, we solve for x

11x = 22 ← Divide both sides by 11

x = 2 ← The answer

D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:

5(2)+2y = 22

10 + 2y = 22

2y = 12

y = 6

Therefore, the solution to this problem is x = 2 and y = 6

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Make y the subject of the formula:A = xy + yz

Vedmedyk [2.9K]

A=xy+yz
A=y*(x+z)
y=A/(x+z)

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3 years ago

Line a is parallel to line b, m∠1=2x +44, and m∠5x+38. Find the value of x.

Soloha48 [4]

$2x + 44 = 5x + 38$
$5x - 2x = 3x$
$44 = 3x + 38$
$44 - 38 = 6$
$6 = 3x$
$2 = x$

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3 years ago

Which graph best represents a function with a range of all real numbers less than or equal to 7

Tamiku [17]

Answer:

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Step-by-step explanation:

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2 years ago

Which number is an irrational number?

xxTIMURxx [149]

Answer:

3.5

Step-by-step explanation:

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3 years ago

Find f such that the given conditions are satisfiedf’(x)=x-4, f(2)=-1

kicyunya [14]

Given:

$f^{\prime}\left(x\right)=x-4,\text{ and}f\left(2\right)=-1$

To find:

The correct function.

Explanation:

Let us consider the function given in option D.

$f(x)=\frac{x^2}{2}-4x+5$

Differentiating with respect to x we get,

$\begin{gathered} f^{\prime}(x)=\frac{2x}{2}-4 \\ f^{\prime}(x)=x-4 \end{gathered}$

Substituting x = 2 in the function f(x), we get

$\begin{gathered} f(2)=\frac{2^2}{2}-4(2)+5 \\ =2-8+5 \\ =-6+5 \\ f(2)=-1 \end{gathered}$

Therefore, the given conditions are satisfied.

So, the function is,

$f(x)=\frac{x^{2}}{2}-4x+5$

Final answer: Option D

6 0

1 year ago