Given :
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by
.
To Find :
Find the time at which the concentration is a maximum. b. Find the maximum concentration.
Solution :
For maximum value of x, K'(x) = 0.

Since, time cannot be negative, so ignoring x = -3 .
Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6
Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.
Hence, this is the required solution.
Im assuing the 0.6 is a percentage and not the number of passes then :
100% - 60% = 40%
Answer:
Step-by-step explanation:
3rd
Answer:
Rule: y = 2x
m = 2
b = 0
Step-by-step explanation:
(17, 34) and (22, 44)
<u>Slope:</u>
m=(y2-y1)/(x2-x1)
m=(44-34)/(22-17)
m= (10)/5
m = 2
<u>Slope-intercept:</u>
y - y1 = m(x - x1)
y - 34 = 2(x - 17)
y - 34 = 2x - 34
y = 2x
y = mx + b
y = 2x
b = 0