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3 years ago

5

A box in the shape of a rectangular prism has the dimensions shown. What is the length of the interior diagonal of the box? Roun

d to the nearest hundredth. Enter your answer in the box.

1 answer:

Zinaida [17]3 years ago

6 0

Answer:

Step-by-step explanation:

44

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Do the following pairs correspond to a function

wel

Yes it is a function

6 0

4 years ago

(PLSSSS HELP) Determine which three out of the six points shown below are a solution to the equation x-3y=22 Plot the three poin

algol [13]

Answer:

$(-2,8)$ $(7,5)$ $(1,7)$

Step-by-step explanation:

Given

$x + 3y = 22$

Solving (a): The possible coordinates

We have:

$(x,y) = (-2,8)$

This gives:

$x + 3y = 22 \to -2 + 3 * 8$

$x + 3y = 22 \to -2 + 24$

$x + 3y = 22 \to 22$

<em>(-2,8) is a point on the grid</em>

$(x,y) = (7,5)$

This gives:

$x + 3y = 22 \to 7 + 3 * 5$

$x + 3y = 22 \to 7 + 15$

$x + 3y = 22 \to 22$

<em>(7,5) is a point on the grid</em>

$(x,y) = (-5,5)$

This gives:

$x + 3y = 22 \to -5 + 3 * 5$

$x + 3y = 22 \to -5 + 15$

$x + 3y = 22 \to 10$

<em>(-5,5) is a not point on the grid</em>

<em></em>

$(x,y) = (1,3)$

This gives:

$x + 3y = 22 \to 1 + 3 * 3$

$x + 3y = 22 \to 1 + 9$

$x + 3y = 22 \to 10$

<em>(1,3) is a not point on the grid</em>

$(x,y) = (1,7)$

This gives:

$x + 3y = 22 \to 1 + 3 * 7$

$x + 3y = 22 \to 1 + 21$

$x + 3y = 22 \to 22$

(1,7) is a point on the grid

So, we plot the following on the grid

$(-2,8)$ $(7,5)$ $(1,7)$

See attachment

8 0

3 years ago

Need help! Will mark Brainiest!

kicyunya [14]

Option B: $y=-\sqrt[3]{x-4}+7$ is the new equation

Explanation:

The given equation is $y=-\sqrt[3]{x}$

We need to find the new graph which is shifted 7 units up and 4 units right.

First, we shall shift the graph 7 units up.

The general formula to shift the graph b units up is given by

$y=f(x)+b$

Thus, to shift the graph 7 units up, let us substitute $b=7$ and $f(x)=-\sqrt[3]{x}$ in the general formula, we have,

$y=$-\sqrt[3]{x}$+7$

Now, we shall shift the graph 4 units right.

The general formula to shift the graph b units right is given by

$y=f(x-b)$

Thus, to shift the graph 4 units right, let us substitute $b=4$ and $f(x)=$-\sqrt[3]{x}+7$$ in the above equation, we have,

$y=-\sqrt[3]{x-4}+7$

Therefore, the new equation is $y=-\sqrt[3]{x-4}+7$

Therefore, Option B is the correct answer.

5 0

3 years ago

How do you solve this problem? 4a-3b+7a=

Inessa05 [86]

In this problem, you combine the like terms...

4a - 3b + 7a

4a and 7a are like terms so you add them together.

4a + 7a = 11a

So, the answer is: 11a - 3b

3 0

3 years ago

what is the constant of variation for the quadratic variation of x |2|3|4|5|6| fx |28|63|112|175|252|

hjlf

F(x) = k*x^2
You can find k using only the first point.
28 = k*2^2
7 = k

The constant of variation is 7.

8 0

3 years ago