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LUCKY_DIMON [66]
2 years ago
7

Find the area of the figure. (Sides meet at right angles.)

Mathematics
1 answer:
Anna71 [15]2 years ago
5 0

Given:

A figure.

To find:

The area of the figure.

Solution:

Draw a line and divide the figure it two parts as shown in the below figure.

From the figure it is clear that the line divides the given figure it two rectangles with dimensions 3 yd by 4 yd and 4 yd by 7 yd.

Area of a rectangle is

Area=Length\times width

Using this formula, the areas of both rectangles are

A_1=3\times 4

A_1=12

And,

A_2=7\times 4

A_2=28

Now, the area of combined figure is

A=A_1+A_2

A=12+28

A=40

Therefore, the area of given figure is 40 sq yd.

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Sam read 20% of the book on Monday and 0.2 of the book on Tuesday. If he read 50% of the remainder on Wednesday and still had 36
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In ΔEFG, the measure of ∠G=90°, EF = 95 feet, and FG = 26 feet. Find the measure of ∠F to the nearest degree.
Firdavs [7]

Answer:

74.4°

Step-by-step explanation:

Given

  • ∠G=90° => ΔEFG is a right triangle
  • EF = 95 feet
  • FG = 26 feet

Use sine law to find ∠F

As we know:

Sin(GEF)/ GF = Sin(EGF)/EF

<=> Sin(GEF) / 26 = Sin(90)/95

<=>Sin(GEF) / 26 = 1/95

<=> Sin(GEF)  = 26/95

<=> ∠GEF ≈ 15.8°

=> ∠F = 180° - ∠G - ∠GEF

∠F = 180° - 90° - 15.8° = 74.4°

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