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LUCKY_DIMON [66]
2 years ago
7

Find the area of the figure. (Sides meet at right angles.)

Mathematics
1 answer:
Anna71 [15]2 years ago
5 0

Given:

A figure.

To find:

The area of the figure.

Solution:

Draw a line and divide the figure it two parts as shown in the below figure.

From the figure it is clear that the line divides the given figure it two rectangles with dimensions 3 yd by 4 yd and 4 yd by 7 yd.

Area of a rectangle is

Area=Length\times width

Using this formula, the areas of both rectangles are

A_1=3\times 4

A_1=12

And,

A_2=7\times 4

A_2=28

Now, the area of combined figure is

A=A_1+A_2

A=12+28

A=40

Therefore, the area of given figure is 40 sq yd.

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Infinito álgebra For -2x-9y=-25 and -4x-9y=-23
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-2x -9y = -25
-(-4x -9y =-23)
2x = -2
x = -1

-2(-1) -9y = -25
2 - 9y = -25
-9y = -25 -2
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7 0
3 years ago
Joe has to take two quizzes tomorrow. He has only enough time to study for one of them. The science quiz has 6 true or false que
finlep [7]

Answer:

C) English

Step-by-step explanation:

I don't really know how to explain it, so I'll show you instead.

For science, there are 6 of 6 correct answers with a 0.5 chance of answering correctly.

So,

0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5 = 0.016

For English, there are 4 of 4 correct answers with a 0.25 chance of answering correctly.

So,

0.25 x 0.25 x 0.25 x 0.25 = 0.004

They will have to study English (0.004) because it is lower than science (0.016).

4 0
2 years ago
Read 2 more answers
Find the distribution of responses about whether there was broken glass at the accident for the subjects in this study using rel
Lemur [1.5K]

Answer:

Probability of having broken glass =  0.1933

Probability of not having broken glass = 0.8067

Step-by-step explanation:

The Treatment table in the file attached to the given question is written out and completed below;

                                                  Treatment

Response       Smashed into             Hit                 Control       Total

      Yes             16                               7                        6             29

       No             34                              43                     44            121

Total:                  50                            50                     50           150

Using relative frequencies,

the distribution of responses about whether there was broken glass at the accident for the subjects in this study can be computed as follows:

Probability of having broken glass = \dfrac{29}{150}

Probability of having broken glass =  0.1933

Probability of not having broken glass = \dfrac{121}{150 }

Probability of not having broken glass = 0.8067

5 0
3 years ago
The set of the consecutive odd numbers 1, 3, 5, 7, ... , N has a sum of 400. How many numbers are in the set?
Amanda [17]

Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.

First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
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Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:

         1, 3, 5, 7, 9, 11, 13, 15 .

Number of items in the set . . . 8
Sum of all the items in the set . . . 64

Hmmm.  That's interesting.  64 happens to be the square of 8 . 
Do you think that might be all there is to it ?

Let's check it out:

Even-numbered lists of odd numbers:

1, 3                                   Items = 2, Sum = 4
1, 3, 5, 7                           Items = 4, Sum = 16
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Amazing !  The sum is always the square of the number of items in the set !

For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.

I slogged through it on my calculator, and it's true.

I never knew this before.  It seems to be something valuable
to keep in my tool-box (and cherish always).


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